A triangle is drawn (Refer to figure 2). ET is perpendicular bisector of HP. State why EH = EP. A. because of the angle bisector theorem B. because of the definition of segment bisector C. because of the perpendicular bisector theorem D. because EO is perpendicular bisector of HP. A B O D
A triangle is drawn (Refer to figure 2). ET is perpendicular bisector of HP. State why EH = EP. A. because of the angle bisector theorem B. because of the definition of segment bisector C. because of the perpendicular bisector theorem D. because EO is perpendicular bisector of HP. A B O D
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter5: Similar Triangles
Section5.6: Segments Divided Proportionally
Problem 38E: In right ABC with right C,AD bisects BAC. If AC=6 and DC=3, find BD and AB. HINT: Let BD=x and...
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![A triangle is drawn (Refer to figure 2). ET is perpendicular
bisector of HP. State why EH = EP.
A. because of the angle bisector theorem
B. because of the definition of segment bisector
C. because of the perpendicular bisector theorem
D. because EO is perpendicular bisector of HP.
ia. 2
A
B
D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F855ccac2-1d52-4c4c-86ab-e15a3900dde7%2Fb467f278-64a6-42e5-9bc8-79e0ac877915%2F8leoo1e_processed.png&w=3840&q=75)
Transcribed Image Text:A triangle is drawn (Refer to figure 2). ET is perpendicular
bisector of HP. State why EH = EP.
A. because of the angle bisector theorem
B. because of the definition of segment bisector
C. because of the perpendicular bisector theorem
D. because EO is perpendicular bisector of HP.
ia. 2
A
B
D
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