A triangle has side lengths of 5 and 8 and an area of 16. Show that there are actually two possible triangles that satisfy these conditions by finding the third side of each triangle AND the angle between the side with length 5 and the side with length 8. Round your answers to two decimal places. With the aid of a protractor and a ruler, draw a reasonably accurate diagram of each triangle.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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A triangle has side lengths of 5 and 8 and an area of 16. Show that there are actually two possible triangles that satisfy these conditions by finding the third side of each triangle AND the angle between the side with length 5 and the side with length 8. Round your answers to two decimal places. With the aid of a protractor and a ruler, draw a reasonably accurate diagram of each triangle. 

Expert Solution
Step 1

Given that 

the two sides of a triangle are 5 and 8

and area of that triangle is 16.

Let sides of the triangle are a=5, b=8, c

and area is A=16.

If s=a+b+c2=13+c2, then

Area will be

A=ss-as-bs-c

A=13+c213+c2-513+c2-813+c2-c

16=13+c23+c2c-3213-c2

132-c24c2-324=162

132-c2c2-32=256×16

-c4+132+32c2-169×9=4096

c4-178c2+5617=0

c2=178±1782-456172=178±92162=178±962

Taking positive sign, we get 

c2=178+962=2742=137

c=137=11.70

and taking negative sign, we get

c2=178-962=822=41

c=41=6.40

So two possible triangles are (5,8,11.70) and (5,8,6.40) which has same area as 16.

 

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