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A traveler pulls on a suitcase strap at an angle 36° above the horizontal. If 908 J of work are done by the strap while moving the suitcase a horizontal distance of 15 m, what is the tension in the strap? O 61 N O 92 N O 85 N O 75 N

A traveler pulls on a suitcase strap at an angle 36° above the horizontal. If 908 J of work are done by the strap while moving the suitcase a horizontal distance of 15 m, what is the tension in the strap? O 61 N O 92 N O 85 N O 75 N

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Doing some physics homework and am kind of stumped here!

**Physics Problem: Calculating Tension** A traveler pulls on a suitcase strap at an angle of 36° above the horizontal. If 908 J of work are done by the strap while moving the suitcase a horizontal distance of 15 m, what is the tension in the strap? ### Options: - ○ 61 N - ○ 92 N - ○ 85 N - ○ 75 N To solve this, consider the work done equation: \[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \] Where: - Work = 908 J - Distance = 15 m - θ = 36° - Force is the tension in the strap ### Explanation: 1. Use the relationship and solve for Force (Tension): \[ 908 = T \times 15 \times \cos(36^\circ) \] 2. Calculate \(\cos(36^\circ)\), then solve for \(T\).
Transcribed Image Text:**Physics Problem: Calculating Tension** A traveler pulls on a suitcase strap at an angle of 36° above the horizontal. If 908 J of work are done by the strap while moving the suitcase a horizontal distance of 15 m, what is the tension in the strap? ### Options: - ○ 61 N - ○ 92 N - ○ 85 N - ○ 75 N To solve this, consider the work done equation: \[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \] Where: - Work = 908 J - Distance = 15 m - θ = 36° - Force is the tension in the strap ### Explanation: 1. Use the relationship and solve for Force (Tension): \[ 908 = T \times 15 \times \cos(36^\circ) \] 2. Calculate \(\cos(36^\circ)\), then solve for \(T\).
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