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A transparent sphere of unknown composition is observed to form an image of the Sun on its surface opposite the Sun. What is the refractive index of the sphere material? Step 1 As parallel rays from the Sun (object distance p → ∞) enter the transparent sphere from air (index of refraction n₁ = 1.00), the center of curvature of the surface is on the side of the sphere that the light is going toward, that is, the back side of the sphere. Thus, the radius of curvature R is the radius of the sphere and R > 0. Since it is observed that a real image is formed on the surface of the sphere that is opposite the Sun, the image distance q is the diameter of the sphere, q = +2R. The object distance p, the image distance q, and the radius of curvature R are related by the equation 0₁ P giving + where n₁ is the index of refraction of air and n₂ is the index refraction on the inside of the spherical surface. Let n represent the index of refraction of the sphere material in this problem (n₂ = n). The equation becomes n 2R which reduces to n = 2n- 0 + 7₂ 9 n = = R

A transparent sphere of unknown composition is observed to form an image of the Sun on its surface opposite the Sun. What is the refractive index of the sphere material? Step 1 As parallel rays from the Sun (object distance p → ∞) enter the transparent sphere from air (index of refraction n₁ = 1.00), the center of curvature of the surface is on the side of the sphere that the light is going toward, that is, the back side of the sphere. Thus, the radius of curvature R is the radius of the sphere and R > 0. Since it is observed that a real image is formed on the surface of the sphere that is opposite the Sun, the image distance q is the diameter of the sphere, q = +2R. The object distance p, the image distance q, and the radius of curvature R are related by the equation 0₁ P giving + where n₁ is the index of refraction of air and n₂ is the index refraction on the inside of the spherical surface. Let n represent the index of refraction of the sphere material in this problem (n₂ = n). The equation becomes n 2R which reduces to n = 2n- 0 + 7₂ 9 n = = R

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A transparent sphere of unknown composition is observed to form an image of the Sun on its surface opposite the Sun. What is the refractive index of the sphere material? Step 1 As parallel rays from the Sun (object distance p → ∞) enter the transparent sphere from air (index of refraction n₁ = 1.00), the center of curvature of the surface is on the side of the sphere that the light is going toward, that is, the back side of the sphere. Thus, the radius of curvature R is the radius of the sphere and R > 0. Since it is observed that a real image is formed on the surface of the sphere that is opposite the Sun, the image distance q is the diameter of the sphere, q = +2R. The object distance p, the image distance q, and the radius of curvature R are related by the equation 0₁ P giving + where n₁ is the index of refraction of air and n₂ is the index refraction on the inside of the spherical surface. Let n represent the index of refraction of the sphere material in this problem (n₂ = n). The equation becomes n 2R which reduces to n = 2n- 0 + 7₂ 9 n = = R
Transcribed Image Text:A transparent sphere of unknown composition is observed to form an image of the Sun on its surface opposite the Sun. What is the refractive index of the sphere material? Step 1 As parallel rays from the Sun (object distance p → ∞) enter the transparent sphere from air (index of refraction n₁ = 1.00), the center of curvature of the surface is on the side of the sphere that the light is going toward, that is, the back side of the sphere. Thus, the radius of curvature R is the radius of the sphere and R > 0. Since it is observed that a real image is formed on the surface of the sphere that is opposite the Sun, the image distance q is the diameter of the sphere, q = +2R. The object distance p, the image distance q, and the radius of curvature R are related by the equation 0₁ P giving + where n₁ is the index of refraction of air and n₂ is the index refraction on the inside of the spherical surface. Let n represent the index of refraction of the sphere material in this problem (n₂ = n). The equation becomes n 2R which reduces to n = 2n- 0 + 7₂ 9 n = = R
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