A trainee in a medical lab will be released to work on her own when her results agree with the accepted value of 13.95 mg/dL at a 95% confidence level. Results of a blood urea nitrogen analysis are shown below. Trainee: x= 14.57 mg/dL s= 0.45 mg/dL n= 6 samples Should the trainee be released to work alone? Explain your answer.

A trainee in a medical lab will be released to work on her own when her results agree with the accepted value of 13.95 mg/dL at a 95% confidence level. Results of a blood urea nitrogen analysis are shown below. Trainee: x= 14.57 mg/dL s= 0.45 mg/dL n= 6 samples Should the trainee be released to work alone? Explain your answer.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Data obtained: Chips # of extractions Chips' weight (g) Fat weight (g) Regular 3 20.043 6.745 3 20.187 6.438 3 20.198 7.451 Low fat 3 19.456 3.982 3 20.072 4.547 3 20.192 4.589 Mass percent is a method of expressing the concentration of a substance in a mixture or element in a compound. It is calculated as the mass of the component divided by the total mass of the mixture and then multiplied by 100 to get the percent. The formula is: mass % of component= (mass of component / total mass) x 100% 1) Reproduce the following table, and use the data to determine the mass % of fat in the chips for each trial. 2) Show one example calculation. Chips Trial % by mass of fat Regular 1 2 3 Lowfat 1 2 3
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NaOH Concentration (M): 0.09669M Trial 1: Inital Volume of NaOH: 0.55mL Final Volume of NaOH: 28.25 mL Trail 2: Intial Volume of NaOH: 18.1 mL Final Volume of NaOH: 46.1 mL Concentration of HCl Solution Subtract the initial buret reading from the end point reading. Convert the readings to liters by dividing by 1000. Solve this equation for the concentration of HCl: (CHCl) (0.01000 liters ) = (CNaOH) (volume of NaOH in liters). CNaOH is the normality of the NaOH you recorded from the bottle. Average the two HCl concentrations.
SHOW COMPLETE SOLUTION AND BOX THE FINAL ANSWER.
A student prepares a 3.4M aqueous solution of propionic acid (C₂H₂CO₂H). Calculate the fraction of propionic acid that is in the dissociated form in his solution. Express your answer as a percentage. You will probably find some useful data in the ALEKS Data resource. Round your answer to 2 significant digits. % x10 X 5
Q) A student misreads the directions and adds 4.0 g of benzoic acid instead of 0.4 g. What do you expect to happen? Would the experiment still be valid? Explain your reasoning. Pure Lauric Acid Lauric Acid + 0.4 g Benzoic Acid Lauric Acid + 0.5 g Benzoic Acid Mass of Lauric Acid 3.03g 3.00g 3.00g Mass of Benzoic Acid 0 g 0.40g 0.50g Freezing Point 43’C 39’C 38’C Freezing Point Depression * 4’C 5’C Molality of Benzoic Acid in Lauric Acid* 1.026 mol/kg 1.282 mol/kg Moles of Benzoic Acid * 0.003 moles 0.004 moles Experimental Molar Mass of Benzoic Acid * 133.3g/mol 125 g/mol Average Molar Mass * 129.15g/mol Percent Error * 5.75%
Using the calibration curve below (equation of the line: y=0.0039x + 0.9981) to determine the percentage of sugar in a sugar water solution with a density of 1.034 g/mL. Density versus Percent Sugar 1.07 1.06 y = 0.0039x + 0.9981 R² = 0.9998 1.05 1.04 1.03 1.02 1.01 1 0.99 6 8 10 12 14 16 Percent Sugar (% m/m ) 8.5% 1.0% 9.2% 4.2 % 9.9% Density (g/mL) 2.
View Assessment ← C Pri Ter Acc X 13 minutes remaining Question 1 blackboard.matc.edu/ultra/courses/_525703_1/outline/assessment/_1556 Blank 1 X Blank 2 Blank 3 All answers must have the correct units. Watch your significant digits! A 55.0 g sample of sugar (C12H22011) is dissolved in 170. g of water. a. What is the mass of the solute? Blank 1 g b. What is the mass of the solvent? Blank 2 g c. What is the mass of the solution? Blank 3 g d. What is the percentage by mass of this solution? (% m/m) Blank 4 % Blank 4 Add your answer Add your answer Add your answer Add your answer Courses Last saved 12:59:40 PM X Questions Filter (6) ▼ + K First < Previous Next
An impure sample contains 1.01 g of impurities and 4.92 g of benzoic acid. The impure sample is dissolved in water, then heated. The solution is then cooled. How many grams of benzoic acid will recrystallize when the solution has cooled? Include the unit and two decimal places in your answer. The solubilities of the impurity and benzoic acid in hot water are found as an item in the Recrystallization Experiment folder. Solubility Data for Report Questions 10 Compound Cold Water solubility Hot Water Solubility Benzoic acid 0.42 g per 100 mL of water 5.79 g per 100 mL of water Impurity 0.61 g per 100 mL of water 4.62 g per 100 mL of water
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