A tractor is speeding up at 3 m/s/s while pulling a 1,011 kg sled with a rope at an angle of 23 degrees. The coefficient of kinetic friction between the sled and ground is 0.3. What is the tension (Newtons) in the rope? (g=9.8 m/s?)

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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Problem Description:**

A tractor is speeding up at 3 m/s² while pulling a 1,011 kg sled with a rope at an angle of 23 degrees. The coefficient of kinetic friction between the sled and the ground is 0.3. What is the tension (in Newtons) in the rope? (g = 9.8 m/s²)

**Analysis:**

To solve this problem, we'll need to use the principles of Newton's second law and frictional force calculations. The tension in the rope will have both horizontal and vertical components because of the angle. The frictional force needs to be calculated to find the net force required for the given acceleration.

**Steps to Solve:**

1. **Identify Forces**:
   - Gravitational force.
   - Normal force.
   - Frictional force.
   - Tension in the rope.
  
2. **Resolve Tension into Components**:
   - Horizontal component: \(T \cos(23^\circ)\)
   - Vertical component: \(T \sin(23^\circ)\)

3. **Calculate Frictional Force**:
   - \(F_f = \mu \times N\), where \(N\) is the normal force.

4. **Equations of Motion**:
   - In the vertical direction, find the normal force from the balance of forces.
   - In the horizontal direction, apply Newton's second law to find the tension.

5. **Use Newton's Second Law**:
   - \(F_{\text{net}} = m \cdot a = T_{\text{horizontal}} - F_f\)

Solving these equations will provide the value for the tension in the rope.
Transcribed Image Text:**Problem Description:** A tractor is speeding up at 3 m/s² while pulling a 1,011 kg sled with a rope at an angle of 23 degrees. The coefficient of kinetic friction between the sled and the ground is 0.3. What is the tension (in Newtons) in the rope? (g = 9.8 m/s²) **Analysis:** To solve this problem, we'll need to use the principles of Newton's second law and frictional force calculations. The tension in the rope will have both horizontal and vertical components because of the angle. The frictional force needs to be calculated to find the net force required for the given acceleration. **Steps to Solve:** 1. **Identify Forces**: - Gravitational force. - Normal force. - Frictional force. - Tension in the rope. 2. **Resolve Tension into Components**: - Horizontal component: \(T \cos(23^\circ)\) - Vertical component: \(T \sin(23^\circ)\) 3. **Calculate Frictional Force**: - \(F_f = \mu \times N\), where \(N\) is the normal force. 4. **Equations of Motion**: - In the vertical direction, find the normal force from the balance of forces. - In the horizontal direction, apply Newton's second law to find the tension. 5. **Use Newton's Second Law**: - \(F_{\text{net}} = m \cdot a = T_{\text{horizontal}} - F_f\) Solving these equations will provide the value for the tension in the rope.
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