A toy submarine of mass m = 0.580 kg moves around a submerged circular track of radius R = 2.02 m. The submarine's engine provides a constant propulsion force of F = 5.13 N. When the sub is in motion, it is subject to a R. viscous drag force exerted by the water. This force is proportional to the sub's speed; the proportionality factor is C = 1.26 kg/s. Assuming it starts from rest at t = 0 s, the speed v(t) of the submarine at a later time t is given by F v (t) = (1 – e Culm) 000 where e is the base of the natural logarithm. 1600 How much time has passed when the submarine's speed reaches 64% of its terminal value? t = 0.4703 What is the magnitude of the submarine's acceleration a at this time? a = 3.184 m/s2 Incorrect
A toy submarine of mass m = 0.580 kg moves around a submerged circular track of radius R = 2.02 m. The submarine's engine provides a constant propulsion force of F = 5.13 N. When the sub is in motion, it is subject to a R. viscous drag force exerted by the water. This force is proportional to the sub's speed; the proportionality factor is C = 1.26 kg/s. Assuming it starts from rest at t = 0 s, the speed v(t) of the submarine at a later time t is given by F v (t) = (1 – e Culm) 000 where e is the base of the natural logarithm. 1600 How much time has passed when the submarine's speed reaches 64% of its terminal value? t = 0.4703 What is the magnitude of the submarine's acceleration a at this time? a = 3.184 m/s2 Incorrect
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![22 of 25
O Attempt 2
A toy submarine of mass m = 0.580 kg moves around a
R.
submerged circular track of radius R = 2.02 m. The
%3D
submarine's engine provides a constant propulsion force of
F = 5.13 N. When the sub is in motion, it is subject to a
viscous drag force exerted by the water. This force is
proportional to the sub's speed; the proportionality factor is
C = 1.26 kg/s. Assuming it starts from rest at t = 0 s, the
speed v(t) of the submarine at a later time t is given by
%3D
F
v(1) =-(1 – e-Cilm)
%3D
where e is the base of the natural logarithm.
How much time has passed when the submarine's speed
t 3D
0.4703
reaches 64% of its terminal value?
What is the magnitude of the submarine's acceleration a at
m/s?
3.184
a =
this time?
Incorrect](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F750615da-c5fa-4cb6-9705-37000bef8bfc%2F773831c1-2374-4807-971a-c2910a39fe60%2Fnybkpug_processed.jpeg&w=3840&q=75)
Transcribed Image Text:22 of 25
O Attempt 2
A toy submarine of mass m = 0.580 kg moves around a
R.
submerged circular track of radius R = 2.02 m. The
%3D
submarine's engine provides a constant propulsion force of
F = 5.13 N. When the sub is in motion, it is subject to a
viscous drag force exerted by the water. This force is
proportional to the sub's speed; the proportionality factor is
C = 1.26 kg/s. Assuming it starts from rest at t = 0 s, the
speed v(t) of the submarine at a later time t is given by
%3D
F
v(1) =-(1 – e-Cilm)
%3D
where e is the base of the natural logarithm.
How much time has passed when the submarine's speed
t 3D
0.4703
reaches 64% of its terminal value?
What is the magnitude of the submarine's acceleration a at
m/s?
3.184
a =
this time?
Incorrect
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