Fp = Fg b vž = mg mg Vr = b Mr. Aikins dropped from a height of 7.7 km. In less than 20 seconds he had descended 1 km in altitude and had reached terminal speed. But because the density of the air is not constant, it is higher at lower altitude, its terminal velocity slowly decreases as it falls. The density of air is 1.22 kg / m^3 at sea level and 1.11 kg / m^3 at 1 km altitude. Aikins data: mass = 90.8 kg, horizontal body area = 0.56 m^2, Cd = 1.0
Fp = Fg b vž = mg mg Vr = b Mr. Aikins dropped from a height of 7.7 km. In less than 20 seconds he had descended 1 km in altitude and had reached terminal speed. But because the density of the air is not constant, it is higher at lower altitude, its terminal velocity slowly decreases as it falls. The density of air is 1.22 kg / m^3 at sea level and 1.11 kg / m^3 at 1 km altitude. Aikins data: mass = 90.8 kg, horizontal body area = 0.56 m^2, Cd = 1.0
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Transcribed Image Text:F, = Fg
b vž = mg
mg
Vr =
b
Mr. Aikins dropped from a height of 7.7 km. In less than 20 seconds he had descended 1 km
in altitude and had reached terminal speed. But because the density of the air is not
constant, it is higher at lower altitude, its terminal velocity slowly decreases as it falls. The
density of air is 1.22 kg / m^3 at sea level and 1.11 kg / m^3 at 1 km altitude.
Aikins data: mass = 90.8 kg, horizontal body area = 0.56 m^2, Cd = 1.0
a) Determine the value of the constant b:
b =
kg / m
b) Determine the terminal velocity at 1 km height:
UT =
m/s
c) Convert your result from uT to mph:
UT =
mph
d) Search the web for information about the 2016 Luka Aikins jump and get his terminal
speed:
vLuka =
m/s
e) Determine the % difference between steps c and d:
% diff. =
%
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