Question 6 hATop ViewCart A is traveling east when it collides with cart B, which ís traveling north. Cart A has a mass of 3.05 kg, and cart B has a mass of 2.10 kg. The two carts travel together as a single object on a horizontal surface at an angle 0 relative to due east, as shown above.In another trial, the speed of the carts immediately after the collision is 0.60 m/s, and the carts slide 0.24 m on the horizontal surface before coming to rest. The coefficient of kinetic friction between the sliding carts and the surface is most nearly Top ViewТopCart A is traveling east when it collides with cart B, which is traveling north. Cart A has a mass of 3.05 kg, and cart B has a mass of 2.10 kg. The two carts travel together as a single object on a horizontal surface at an angle 0 relative to due east, as shown above.In another trial, the speed of the carts immediately after the collision is 0.60 m/s, and the carts slide 0.24 m on the horizontal surface before coming to rest. The coefficient of kinetic friction between the sliding carts and the surface is most nearly0.08B0.13C0.19D0.25E0.75

Kinetic friction comes into account when an object moves relative to a surface. It always oppose the motion of object. If an object moves and kinetic friction is present here then after travelling a certain distance object comes to rest.Mass of cart A = m1 = 3.05 kg Mass of cart B = m2 = 2.10 kg As two carts travel together as a single object, so mass of single object is M = (m1 + m2) = 3.05 + 2.10 = 5.15 kg Speed of carts immediately after collision = V1 = 0.60 m/s Distance covered by cart before coming to rest = S = 0.24 m As carts coming to rest, so final speed of carts = V2 = 0 Let coefficient of kinetic friction = uk It shows the initial position of object and shows the final position of object. We have, N = force on object due to surface (upward) .fk = kinetic friction between object and surface and it always oppose the motion. It acts along left as motion is along right .g = acceleration are to gravity = 9.81 ms-2 Mg = weight of object (downward) Let acceleration of object = a (along horizontal direction of a is same as that of net force on object. As there is no motion along vertical, so net force along vertical is zero. Now, net force along vertical = Fv = N – Mg As Fv = 0 N – M = 0 N = M Now kinetic friction is given by fk = ukN = ukMg Net force on object along horizontal = Fh = -fk (here, we choose vertical upward and right as positive and vertical downward and left as negative) Fh = -ukMg Using Newton’s law along horizontal, we have Net force = mass x acceleration Fh = Ma -ukMg = Ma (Newton’s 2nd law) .a = -ukg Now using equation of motion V2 = u2 + as --- 1 Where V is final speed of object .u is the initial speed of object .a is the acceleration of object .s is distance covered by object V2 = V2 + 2as V2 = V2 + 2(-ukg)sV2 = V2 + 2(-ukg)s 0 = (0.60)2 - 2 x uk (9.81)(0.24) 0 = 0.36 m2s-2 – (4.7088m2s-2)uk .uk = = 0.36 m2s-2 / 4.7088m2s-2 = 0.08 So, coefficient of kinetic friction between carts and surface is 0.08.

Answered: A Top View Cart A is traveling east…