A titration curve was generated for the titration of 25.00 mL of 0.1000 M - with 0.05000 M Ag*. Thedissociation reaction for Agl is:Agl(s) = Ag* + -Ksp=[Ag*][l-] = 8.3 x 10-17 1. What volume of the titrant is needed to reach the equivalence point?a. 100.00 mLb. 50.00 mLc. 25.00 mLd. 10.00 mLe. 5.00 ml2. At what pAg will the midpoint of the steep section of the titration curve correspond?a. 1.30b. 4.02C. 8.04d. 12.06e. 16.083. If the concentrations were instead doubled, i.e., Ag titrant was 0.1000 M and I- was0.2000 M, what do you think will happen to the pAg at the equivalence point whencompared to the original?a. It will be doubled.b. It will be halved.c. It will be squared.d. It will be the square root.e. It will be the same.4. If the concentrations were doubled as in the item above, what do you think will happen tothe shape of the titration curve with respect to the original?a. It will be inverted.b. It will be wider vertically.c. It will be wider horizontally.d. It will be wider both vertically and horizontally.e. It will be exactly like the original.

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A titration curve was generated for the titration of 25.00 mL of 0.1000 MI- with 0.05000 M Ag*. The dissociation reaction for Agl is: Agl(s) = Ag* + |- Ksp=[Ag*][l-] = 8.3 × 10-17

A titration curve was generated for the titration of 25.00 mL of 0.1000 MI- with 0.05000 M Ag. The dissociation reaction for Agl is: Agl(s) = Ag + |- Ksp=[Ag*][l-] = 8.3 × 10-17

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

A titration curve was generated for the titration of 25.00 mL of 0.1000 M - with 0.05000 M Ag*. The
dissociation reaction for Agl is:
Agl(s) = Ag* + -
Ksp=[Ag*][l-] = 8.3 x 10-17

1. What volume of the titrant is needed to reach the equivalence point?
a. 100.00 mL
b. 50.00 mL
c. 25.00 mL
d. 10.00 mL
e. 5.00 ml
2. At what pAg will the midpoint of the steep section of the titration curve correspond?
a. 1.30
b. 4.02
C. 8.04
d. 12.06
e. 16.08
3. If the concentrations were instead doubled, i.e., Ag titrant was 0.1000 M and I- was
0.2000 M, what do you think will happen to the pAg at the equivalence point when
compared to the original?
a. It will be doubled.
b. It will be halved.
c. It will be squared.
d. It will be the square root.
e. It will be the same.
4. If the concentrations were doubled as in the item above, what do you think will happen to
the shape of the titration curve with respect to the original?
a. It will be inverted.
b. It will be wider vertically.
c. It will be wider horizontally.
d. It will be wider both vertically and horizontally.
e. It will be exactly like the original.

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