A time study of an employee assembling peanut valves resulted in the following set of observations. What is the standard time, given a performance rating of109 percent and an allowance of 21 percent of the total normal time?Average Time (seconds)15Observations1616182312The standard time isseconds. (Enter your response rounded to two decimal places.)

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Answered: A time study of an employee assembling…

Practical Management Science

6th Edition

ISBN:9781337406659

Author:WINSTON, Wayne L.

Publisher:WINSTON, Wayne L.

Chapter2: Introduction To Spreadsheet Modeling

Section: Chapter Questions

Problem 20P: Julie James is opening a lemonade stand. She believes the fixed cost per week of running the stand...

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A Methods and Measurements Analyst needs to develop a time standard for a certain task. The task involves use of a ruler, square, and portable electric saw to mark and cut the "notch" in a rafter (a standard carpentry task of home construction). In a preliminary study, he observed one of his workers performing this task five times. The observations were made in an air-conditioned, well-lit training facility, at ground level, with all tools and equipment clean and readily available. Observation: 1 2 3 4 5 Task time (seconds): 82 74 80 88 76 (a) What is the actual average time for this task? (b) What is the normal time for this task if the employee worked at a 10% faster pace than is typical for adequately trained workers? (c) What is standard time for this task if allowances sum to 12%? (d) If the analyst then thought more carefully about his experiment and decided that the allowances needed to be increased to match the real (outside, not…
A time study has revealed an average observed timeof 5 minutes, with a standard deviation of 1.25 minu tes. Thesefigures are based on a sample of 75 cycles. Is this sample largeenough for analyst Anand Paul to be 99.73% confident that thestandard time is within 5% of the true value?
An analyst has been asked to prepare an estimate of the proportion of time that a turret lathe operator spends adjusting the machine, with 90% confidence level. Based on previous experience, the analyst believes the proportion will be approximately 30%. a. If the analyst uses sample size of 400 observations, what is the maximum error that will be associated with the estimate? b. What sample size would the analyst need in order to have the maximum error be no more than +/- 5%?
5. The manager of Asombrado Bounty Office, Charles Badillo, estimates his employees are idle 25%of the time. With that problem, how many work samples are needed to consider within 3%accuracy and have 95.45% confidence level. 6. At ASP Micro Manufacturing, Inc. workers press semiconductor into predrilled slots on printed-circuit boards. Determine the normal time of the operation in seconds. The elemental motions for normal time used by the company are as follows:• Reach 6 inches for semiconductors 10.5 TMU• Grasp the semiconductors 8.0 TMU• Move semiconductor to printed-circuit board 9.5 TMU• Position semiconductor 20.1 TMU• Press semiconductor into slots 20.3 TMU• Move board aside 15.8 TMU 7. The semiconductor used in Costin Calculator has 5 components with the consistency of 90%, 95%,98%, 90%, and 99%, respectively. How reliable is one product of calculator?
At Dominos pizza the time study restaurant yielded an average observed time of 4.0 minutes. The analyst rates the observed worker at 85%.this means the worker performed at 85% of normal when the study was made. The firm uses a 13% allowance factor. What is the standard time for this operation. 9.3 min 3.4 min ✓ 3.9 min 3.8 min
Claudine Soosay recorded the following times assembling a watch: Observation No. 1 2 3 4 5 6 7 8 Performance rating is given as 95%. a) The average time of Claudine for the operation = Time (minutes) 0.11 0.09 0.11 0.09 0.15 0.10 0.09 0.10 Observation No. 9 10 11 12 13 14 15 16 minutes (round your response to three decimal places). Time (minutes) 0.11 0.09 0.11 0.10 0.11 0.12 0.14 0.10
The results of a time study to perform a quality control test are shown in the following table: *Disregard employee is smoking a cigarette (included in personal time). The allowance factor is given to be 25%. a) The normal time for the complete operation = b) The standard time for this process = Performance Observation (minutes per cycle) Element Rating 1 2 3 4 5 1 95% 1.5 1.8 23 2 110% 0.8 0.5 90% 0.5 0.4 4 85% 0.6 0.9 8549 1.8 1.9 1.4 0.6 3.7* 0.6 0.6 0.4 0.4 0.7 0.7 0.7 minutes (round your response to two decimal places). minutes (round your response to two decimal places).
Q2 (a) A time study analyst timed an assembly operation for 30 cycles, and then computed the average time per cycle, which was 18.75 minutes. The analyst assigned a performance rating of 0.96 and decided that an appropriate allowance was 15 percent. Assume the allowance factor is based on the workday. Determine the following: (i) Observed time (OT) (ii) The Normal times (NT) (iii) The standard time (ST) (b) If the analyst wants to estimate the number of observations that will be needed to achieve a specified maximum error, with a confidence of 95.5 %. A preliminary study yielded a mean of 5.2 minutes and a standard deviation of 1.1 minutes. Determine the total number of observation needed for these two cases: (a) A maximum error of + or - 6 % (b) A maximum error of 40 minutes
From a time study, the worker’s average observed time for a particular task is shown to be 5.6 minutes. The analyst feels the worker was performing their task, on average, about 25% faster than normal. What would be the resulting standard time assuming a 20% allowance for fatigue and personal needs?
An analyst made 30 observations over 15 minutes during which 12 units where produced. For 9 observations, the worker was seen working. Compute for the observed time.
Compare stopwatch time study and work sampling.
company from your understanding. 3) Calculate the standard time for an operation from the following data. Average observed time for manual elements = 4 0 minutes Average auto cycle time = 3 minutes Rating on a scale of 100 = 90% Personal & other allowances = 15% of basic time

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