A three-phase synchronous generator is connected to a step-up 3¢ transformer T1, which is connected to a 60 km transmission line. At the far end of the line, a step-down transformer bank T2 is connected. The secondary of T2 supplies two synchronous motor loads M1 and M2. The ratings of the equipment are as follows: 10 MVA, 13.8 kV, 12 MVA, 13.8/138 kV, 138/12 kV, 12 kV, 12 kV, 138 kV, X = 30%, X = 10%, X = 9%, X = 25%, X = 30%, X = 0.3 N/km Gen: wye T1: T2: M1: 12 MVA, 4 MVA, 3 MVA, delta-wye wye-delta wye M2: wye T-line: %3| (a) Draw the per-phase equivalent circuit of the system showing all reactances in and the base voltages used at various parts of the network. Choose the generator ratings as bases in the generator circuit. per unit (b) For a three-phase fault on the low-voltage terminals of transformer T2, calculate the steady-state short-circuit current magnitude in amperes supplied by the generator as- suming that all internal voltages are 1.0° pu. Ignore the motor contributions to the fault current for now.

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A three-phase synchronous generator is connected to a step-up 3¢ transformer T1, which is
connected to a 60 km transmission line. At the far end of the line, a step-down transformer
bank T2 is connected. The secondary of T2 supplies two synchronous motor loads M1 and
M2. The ratings of the equipment are as follows:
10 MVA,
12 MVA, 13.8/138 kV,
12 MVA,
4 MVA,
3 MVA,
X = 30%,
X = 10%,
X = 9%,
X = 25%,
X = 30%,
X = 0.3 2/km
Gen:
13.8 kV,
wye
delta-wye
wye-delta
T1:
138/12 kV,
12 kV,
12 kV,
138 kV,
T2:
M1:
wye
M2:
wye
%3|
T-line:
(a) Draw the per-phase equivalent circuit of the system showing all reactances in
and the base voltages used at various parts of the network. Choose the generator ratings
as bases in the generator circuit.
per
unit
(b) For a three-phase fault on the low-voltage terminals of transformer T2, calculate the
steady-state short-circuit current magnitude in amperes supplied by the generator as-
suming that all internal voltages are 1.020° pu. Ignore the motor contributions to the
fault current for now.
Transcribed Image Text:A three-phase synchronous generator is connected to a step-up 3¢ transformer T1, which is connected to a 60 km transmission line. At the far end of the line, a step-down transformer bank T2 is connected. The secondary of T2 supplies two synchronous motor loads M1 and M2. The ratings of the equipment are as follows: 10 MVA, 12 MVA, 13.8/138 kV, 12 MVA, 4 MVA, 3 MVA, X = 30%, X = 10%, X = 9%, X = 25%, X = 30%, X = 0.3 2/km Gen: 13.8 kV, wye delta-wye wye-delta T1: 138/12 kV, 12 kV, 12 kV, 138 kV, T2: M1: wye M2: wye %3| T-line: (a) Draw the per-phase equivalent circuit of the system showing all reactances in and the base voltages used at various parts of the network. Choose the generator ratings as bases in the generator circuit. per unit (b) For a three-phase fault on the low-voltage terminals of transformer T2, calculate the steady-state short-circuit current magnitude in amperes supplied by the generator as- suming that all internal voltages are 1.020° pu. Ignore the motor contributions to the fault current for now.
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