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A third-party survey was conducted on 200 residents in a town south of Phoenix, Arizona about the planned restoration of an old historic building. 114 residents agree to the plan even if this might require the residents to do fund raising activities to augment the cost of restoration. Find a two-sided 95% confidence interval for the proportion of residents favoring the restoration. What interpretation can we infer about the width of the confidence interval, sample size, population proportion and standard error p(1-p)/n of the point estimator 6. O a. 0.4355

A third-party survey was conducted on 200 residents in a town south of Phoenix, Arizona about the planned restoration of an old historic building. 114 residents agree to the plan even if this might require the residents to do fund raising activities to augment the cost of restoration. Find a two-sided 95% confidence interval for the proportion of residents favoring the restoration. What interpretation can we infer about the width of the confidence interval, sample size, population proportion and standard error p(1-p)/n of the point estimator 6. O a. 0.4355

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section: Chapter Questions
Problem 25SGR
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CI for a Population Proportion A third-party survey was conducted on 200 residents in a town south of Phoenix, Arizona about the planned restoration of an old historic building. 114 residents agree to the plan even if this might require the residents to do fund raising activities to augment the cost of restoration. Find a two-sided 95% confidence interval for the proportion of residents favoring the restoration. What interpretation can we infer about the width of the confidence interval, sample size, population proportion and standard error p(1– p)/n of the point estimator 6. a. 0.4355 <p< 0.7045. This is a narrow confidence interval. Although the sample size (n = 200) does not appear to be small, the value of 6 is fairly small, which leads to a large standard error for p Ob. 0.5014 <p < 0.6386. This is a wide confidence interval. Although the sample size (n does not appear to be small, the value of p doesn't quite represent the class of interest, which leads to a large standard error for ôp. 200) C. 0.4355 <p<0.7045. This is a narrow confidence interval. Although the sample size (n = 200) does not appear to be small, the value of p is fairly small, which leads to a large standard error for p d. 0.5014 <p < 0.6386. There appears to be no abnormality in the width of confidence interval. Although the sample size (n = 200) does not appear to be small, the value of p somehow represents the class of interest, which leads to a small standard error for p.
Transcribed Image Text:CI for a Population Proportion A third-party survey was conducted on 200 residents in a town south of Phoenix, Arizona about the planned restoration of an old historic building. 114 residents agree to the plan even if this might require the residents to do fund raising activities to augment the cost of restoration. Find a two-sided 95% confidence interval for the proportion of residents favoring the restoration. What interpretation can we infer about the width of the confidence interval, sample size, population proportion and standard error p(1– p)/n of the point estimator 6. a. 0.4355 <p< 0.7045. This is a narrow confidence interval. Although the sample size (n = 200) does not appear to be small, the value of 6 is fairly small, which leads to a large standard error for p Ob. 0.5014 <p < 0.6386. This is a wide confidence interval. Although the sample size (n does not appear to be small, the value of p doesn't quite represent the class of interest, which leads to a large standard error for ôp. 200) C. 0.4355 <p<0.7045. This is a narrow confidence interval. Although the sample size (n = 200) does not appear to be small, the value of p is fairly small, which leads to a large standard error for p d. 0.5014 <p < 0.6386. There appears to be no abnormality in the width of confidence interval. Although the sample size (n = 200) does not appear to be small, the value of p somehow represents the class of interest, which leads to a small standard error for p.
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