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A third-party survey was conducted on 200 residents in a town south of Phoenix, Arizona about the planned restoration of an old historic building. 114 residents agree to the plan even if this might require the residents to do fund raising activities to augment the cost of restoration. Find a two-sided 95% confidence interval for the proportion of residents favoring the restoration. What interpretation can we infer about the width of the confidence interval, sample size, population proportion and standard error p(1-p)/n of the point estimator 6. O a. 0.4355

A third-party survey was conducted on 200 residents in a town south of Phoenix, Arizona about the planned restoration of an old historic building. 114 residents agree to the plan even if this might require the residents to do fund raising activities to augment the cost of restoration. Find a two-sided 95% confidence interval for the proportion of residents favoring the restoration. What interpretation can we infer about the width of the confidence interval, sample size, population proportion and standard error p(1-p)/n of the point estimator 6. O a. 0.4355

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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CI for a Population Proportion A third-party survey was conducted on 200 residents in a town south of Phoenix, Arizona about the planned restoration of an old historic building. 114 residents agree to the plan even if this might require the residents to do fund raising activities to augment the cost of restoration. Find a two-sided 95% confidence interval for the proportion of residents favoring the restoration. What interpretation can we infer about the width of the confidence interval, sample size, population proportion and standard error p(1– p)/n of the point estimator 6. a. 0.4355 <p< 0.7045. This is a narrow confidence interval. Although the sample size (n = 200) does not appear to be small, the value of 6 is fairly small, which leads to a large standard error for p Ob. 0.5014 <p < 0.6386. This is a wide confidence interval. Although the sample size (n does not appear to be small, the value of p doesn't quite represent the class of interest, which leads to a large standard error for ôp. 200) C. 0.4355 <p<0.7045. This is a narrow confidence interval. Although the sample size (n = 200) does not appear to be small, the value of p is fairly small, which leads to a large standard error for p d. 0.5014 <p < 0.6386. There appears to be no abnormality in the width of confidence interval. Although the sample size (n = 200) does not appear to be small, the value of p somehow represents the class of interest, which leads to a small standard error for p.
Transcribed Image Text:CI for a Population Proportion A third-party survey was conducted on 200 residents in a town south of Phoenix, Arizona about the planned restoration of an old historic building. 114 residents agree to the plan even if this might require the residents to do fund raising activities to augment the cost of restoration. Find a two-sided 95% confidence interval for the proportion of residents favoring the restoration. What interpretation can we infer about the width of the confidence interval, sample size, population proportion and standard error p(1– p)/n of the point estimator 6. a. 0.4355 <p< 0.7045. This is a narrow confidence interval. Although the sample size (n = 200) does not appear to be small, the value of 6 is fairly small, which leads to a large standard error for p Ob. 0.5014 <p < 0.6386. This is a wide confidence interval. Although the sample size (n does not appear to be small, the value of p doesn't quite represent the class of interest, which leads to a large standard error for ôp. 200) C. 0.4355 <p<0.7045. This is a narrow confidence interval. Although the sample size (n = 200) does not appear to be small, the value of p is fairly small, which leads to a large standard error for p d. 0.5014 <p < 0.6386. There appears to be no abnormality in the width of confidence interval. Although the sample size (n = 200) does not appear to be small, the value of p somehow represents the class of interest, which leads to a small standard error for p.
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