A thin square metal plate has a uniform temperature of 80°C on two opposite edges, a temperature of 120°C on the third edge, and a temperature of 60°C on the remaining edge. A mathematical procedure to approximate the temperature at six uniformly spaced interior points results in the following equations: 4T₁-T₂-T6-200 -71 +472-73-75 - 80 T₂ I 4T3 T₂ <= 140 -T3 + 474-75-140 T₂ T₁ 4T5 T6 = 80 I -T₁-T3 + 476 = 200 What is the value of T1, T2, T3, T4, T5 and T6?
A thin square metal plate has a uniform temperature of 80°C on two opposite edges, a temperature of 120°C on the third edge, and a temperature of 60°C on the remaining edge. A mathematical procedure to approximate the temperature at six uniformly spaced interior points results in the following equations: 4T₁-T₂-T6-200 -71 +472-73-75 - 80 T₂ I 4T3 T₂ <= 140 -T3 + 474-75-140 T₂ T₁ 4T5 T6 = 80 I -T₁-T3 + 476 = 200 What is the value of T1, T2, T3, T4, T5 and T6?
Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
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![A thin square metal plate has a uniform temperature of 80°C on two opposite edges, a
temperature of 120°C on the third edge, and a temperature of 60°C on the remaining
edge. A mathematical procedure to approximate the temperature at six uniformly
spaced interior points results in the following equations:
4T₁-T₂-Th
- 200
-7₁ +422-73-75 - 80
T₂ | 4T3 T4 = 140
-T3 + 4T4-T5-140
T₂ T₁ 4T5 T6 = 80
I
-T₁-T₁ + 4T6 = = 200
What is the value of T1, T2, T3, T4, T5 and T6?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4893bc57-11b4-439e-b74b-4878af015430%2F5a6adbd6-eb5f-4b79-b943-0fce4e3c2164%2F4rsi5i8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A thin square metal plate has a uniform temperature of 80°C on two opposite edges, a
temperature of 120°C on the third edge, and a temperature of 60°C on the remaining
edge. A mathematical procedure to approximate the temperature at six uniformly
spaced interior points results in the following equations:
4T₁-T₂-Th
- 200
-7₁ +422-73-75 - 80
T₂ | 4T3 T4 = 140
-T3 + 4T4-T5-140
T₂ T₁ 4T5 T6 = 80
I
-T₁-T₁ + 4T6 = = 200
What is the value of T1, T2, T3, T4, T5 and T6?
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