A thin flake of mica (=1.58) is used to cover one slit of a double-slit interference arrangement. The central point on the viewing screen is now occupied by what had been the seventh bright side fringe . If λ= 550 nm, what is the thickness of the mica? [3]
A thin flake of mica (=1.58) is used to cover one slit of a double-slit interference arrangement. The central point on the viewing screen is now occupied by what had been the seventh bright side fringe . If λ= 550 nm, what is the thickness of the mica? [3]
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A thin flake of mica (=1.58) is used to cover one slit of a double-slit interference
arrangement. The central point on the viewing screen is now occupied by what had been
the seventh bright side fringe . If λ= 550 nm, what is the thickness of the mica? [3]
3. In a Newton’s rings experiment the radii of the nth and (n + 20)th bright rings are found
to be 0.162 and 0.368 cm, respectively, in light of wavelength 546 nm. Calculate the
radius of curvature of the lower surface of the lens. [3]
4. Newton’s rings are observed in reflected light of wavelength 5890A. The diameter of
10th dark ring is 0.50cm. Find the radius of curvature of the lens and air film thickness at
that position.
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