A thermometer is removed from a room where the temperature is 21° C and is taken outside, where the air temperature is -12° C. After one-half minute the thermometer reads 11° C. What is the reading of the thermometer at t = 1 min? (Round your answer to two decimal places.) °C How long will it take for the thermometer to reach -8° C? (Round your answer to two decimal places.) min
A thermometer is removed from a room where the temperature is 21° C and is taken outside, where the air temperature is -12° C. After one-half minute the thermometer reads 11° C. What is the reading of the thermometer at t = 1 min? (Round your answer to two decimal places.) °C How long will it take for the thermometer to reach -8° C? (Round your answer to two decimal places.) min
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
3.2.5
![A thermometer is removed from a room where the temperature is 21° C and is taken outside, where the air temperature is
-12° C. After one-half minute the thermometer reads 11° C. What is the reading of the thermometer at t = 1 min? (Round
your answer to two decimal places.)
°C
How long will it take for the thermometer to reach -8° C? (Round your answer to two decimal places.)
min](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F91ed8060-678c-4d36-a5c7-0e7a65a577a0%2F63136a90-8942-4aa3-a3a2-ad6eededccfd%2Fk3gt9a_processed.png&w=3840&q=75)
Transcribed Image Text:A thermometer is removed from a room where the temperature is 21° C and is taken outside, where the air temperature is
-12° C. After one-half minute the thermometer reads 11° C. What is the reading of the thermometer at t = 1 min? (Round
your answer to two decimal places.)
°C
How long will it take for the thermometer to reach -8° C? (Round your answer to two decimal places.)
min
Expert Solution
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Step 1
Sol:-
To solve this problem, we can use Newton's law of cooling, which states that the rate of change of the temperature of an object is proportional to the difference between the object's temperature and the temperature of its surroundings.
Let T(t) be the temperature of the thermometer at time t. Then, we have:
dT/dt = k(T - Ts)
where k is a constant of proportionality, Ts is the temperature of the surroundings (in this case, -12° C), and dT/dt is the rate of change of the temperature.
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