a) the equivalent resistance was seen by the source = Oa. -6.2505067749104 Ob. 31.252533874552 Oc.-25.002027099642 Od. 15.626266937276 b) the power developed by the source= Oa. -0.03000243251957 Ob. 0.010000810839857 Oc. -0.050004054199283 Od. -0.010000810839857

a) the equivalent resistance was seen by the source = Oa. -6.2505067749104 Ob. 31.252533874552 Oc.-25.002027099642 Od. 15.626266937276 b) the power developed by the source= Oa. -0.03000243251957 Ob. 0.010000810839857 Oc. -0.050004054199283 Od. -0.010000810839857

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Current Division Method

The generalized current divider formula is given by the following relation below,

Question

For R1=65, R2=73, R3=44, R4=66, R5=11, R6=45, R7=76, R8=38, R9=50, R10=71 and I1=0.04 A in the
circuit shown, calculate the following:
R1
11(↓) R10
R9
R&
R7
R2
R4
R6 R3
b) the power developed by the source=
Oa. -0.03000243251957
Ob. 0.010000810839857
Oc. -0.050004054199283
Od. -0.010000810839857
R5
a) the equivalent resistance was seen by the source =
Oa. -6.2505067749104
Ob. 31.252533874552
Oc.-25.002027099642
Od. 15.626266937276

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