A Texas cockroach of mass 0.201 kg runs counterclockwise around the rim of a lazy Susan (a circular disk mounted on a vertical axle) that has a radius 13.5 cm, rotational inertia 6.60 x 10-3 kg-m², and frictionless bearings. The cockroach's speed (relative to the ground) is 1.92 m/s, and the lazy Susan turns clockwise with angular velocity wo = 3.80 rad/s. The cockroach finds a bread crumb on the rim and, of course, stops. (a) What is the angular speed of the lazy Susan after the cockroach stops? (b) Is mechanical energy conserved as it stops? (a) Number i -7.5048 (b) no Units rad/s

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Chapter1: Units, Trigonometry. And Vectors
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**Problem Description:**

A Texas cockroach of mass 0.201 kg runs counterclockwise around the rim of a lazy Susan (a circular disk mounted on a vertical axle) that has a radius of 13.5 cm, rotational inertia of \(6.60 \times 10^{-3} \, \text{kg} \cdot \text{m}^2\), and frictionless bearings. The cockroach's speed (relative to the ground) is 1.92 m/s, and the lazy Susan turns clockwise with an angular velocity \(\omega_0 = 3.80 \, \text{rad/s}\). The cockroach finds a bread crumb on the rim and, of course, stops.

(a) What is the angular speed of the lazy Susan after the cockroach stops?

- **Answer:**
  - Number: \(-7.5048\)
  - Units: \(\text{rad/s}\)

(b) Is mechanical energy conserved as it stops?

- **Answer:** no

**Explanation:**

The setup demonstrates a classic conservation of angular momentum problem. Initially, the system comprising the lazy Susan and the cockroach has combined angular momentum. As the cockroach stops, its linear momentum is transferred to the lazy Susan, altering its angular speed. The example illustrates that mechanical energy is not conserved due to non-conservative forces acting during the cockroach's stop.
Transcribed Image Text:**Problem Description:** A Texas cockroach of mass 0.201 kg runs counterclockwise around the rim of a lazy Susan (a circular disk mounted on a vertical axle) that has a radius of 13.5 cm, rotational inertia of \(6.60 \times 10^{-3} \, \text{kg} \cdot \text{m}^2\), and frictionless bearings. The cockroach's speed (relative to the ground) is 1.92 m/s, and the lazy Susan turns clockwise with an angular velocity \(\omega_0 = 3.80 \, \text{rad/s}\). The cockroach finds a bread crumb on the rim and, of course, stops. (a) What is the angular speed of the lazy Susan after the cockroach stops? - **Answer:** - Number: \(-7.5048\) - Units: \(\text{rad/s}\) (b) Is mechanical energy conserved as it stops? - **Answer:** no **Explanation:** The setup demonstrates a classic conservation of angular momentum problem. Initially, the system comprising the lazy Susan and the cockroach has combined angular momentum. As the cockroach stops, its linear momentum is transferred to the lazy Susan, altering its angular speed. The example illustrates that mechanical energy is not conserved due to non-conservative forces acting during the cockroach's stop.
A 7.43 kg particle with velocity \(\vec{v} = (3.49 \, \text{m/s}) \hat{i} - (9.42 \, \text{m/s}) \hat{j}\) is at \(x = 6.73 \, \text{m}, y = 8.04 \, \text{m}\). It is pulled by a 6.52 N force in the negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the rate at which the angular momentum is changing?

- **(a)** 
  - Number: \(-263.9532\)
  - Units: \(\text{kg} \cdot \text{m}^2/\text{s}\)
  - \(\hat{k}\)

- **(b)**
  - Number: \(-43.87\)
  - Units: \(\text{N} \cdot \text{m}\)
  - \(\hat{k}\)

- **(c)**
  - Number: \(43.87\)
  - Units: \(\text{N} \cdot \text{m}\)
  - \(\hat{k}\)
Transcribed Image Text:A 7.43 kg particle with velocity \(\vec{v} = (3.49 \, \text{m/s}) \hat{i} - (9.42 \, \text{m/s}) \hat{j}\) is at \(x = 6.73 \, \text{m}, y = 8.04 \, \text{m}\). It is pulled by a 6.52 N force in the negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the rate at which the angular momentum is changing? - **(a)** - Number: \(-263.9532\) - Units: \(\text{kg} \cdot \text{m}^2/\text{s}\) - \(\hat{k}\) - **(b)** - Number: \(-43.87\) - Units: \(\text{N} \cdot \text{m}\) - \(\hat{k}\) - **(c)** - Number: \(43.87\) - Units: \(\text{N} \cdot \text{m}\) - \(\hat{k}\)
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