A test statistic based on point estimation is used to construct the decision rule which defines the rejection region (or critical region). True O False
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- What is the critical Z Value? What is the decision making for this hypothesis test? A is the positive critical value for this question, what is/are the possible critical region(s) for this hypothesis test?Application Exercise: Dr. Black is interested in the preference for dog breeds among high school students. He collected the observed frequencies below and wants to know if the breeds are equally preferred. What can be concluded with a = 0.05? Irish Setter Golden Retriever Papillon Great Dane 101 117 83 97 a) Select and compute the appropriate statistic. ---Select--- b) Obtain/compute the appropriate values to make a decision about Ho. Critical Value = ; Test Statistic = Decision: ---Select--- c) Compute the corresponding effect size(s) and indicate magnitude(s). If not appropriate, input and/or select "na" below. Effect Size ; Magnitude: ---Select--- d) Make an interpretation based on the results. There is a significant relationship between dog breeds and high school students. There is a significant dog breed difference among high school students. There is no dog breed difference among high school students.The graph portrays the decision criterion for a one-mean z-test. The curve in the graph is the normal curve for the test statistic under the assumption that the null hypothesis is true. Use the graph to solve the problem. A graphical display of the decision criterion follows. Reject Ho : Do not reject Ho Reject Ho 0.02 0.02 3 2 1 0 i2 3 205 2.05 Determine the critical value(s).
- Statistics students in Oxnard College sampled 11 textbooks in the Condor bookstore and recorded the number of pages in each textbook and its cost. The bivariate data is shown below, Number of Pages (xx) Cost(yy) 942 59.1 453 24.65 789 41.45 473 34.65 302 25.1 567 23.35 482 32.1 511 26.55 285 28.25 529 35.45 477 19.85 Click to Copy-and-Paste DataA student calculates a linear modelyy = xx + . (Please show your answers to two decimal places)Use the model above to estimate the cost when the number of pages is 736Cost = $ (Please show your answer to 2 decimal places.)CHOOSE ALL THAT APPLY: Which of the following are assumptions of ANOVA? Random sample Independent variable(s) are normally distributed Dependent variable is continuous Dependent variable is discrete Treatment variances are similar Treatment means are similar Dependent variables are normally distributedExecutives of a supermarket chain are interested in the amount of time that customers spend in the stores during shopping trips. The mean shopping time, u, spent by customers at the supermarkets has been reported to be 35 minutes, but executives hire a statistical consultant and ask her to determine whether it can be concluded that u is greater than 35 minutes. To perform her statistical test, the consultant collects a random sample of shopping times at the supermarkets. She computes the mean of these times to be 42 minutes and the standard deviation of the times to be 10 minutes. Based on this information, answer the questions below. What are the null hypothesis (H,) and the alternative hypothesis (H,) that should be used for the test? H: u is ? H: u is ? In the context of this test, what is a Type I error? A Type I error is ? fact, u is ? ? v when, in v the hypothesis that u is? v? v. Suppose that the consultant decides to reject the null hypothesis. What sort of error might she be…
- 3Statistics students in Oxnard College sampled 10 textbooks in the Condor bookstore and recorded the number of pages in each textbook and its cost. The bivariate data is shown below, Number of Pages (x) 445 304 721 666 383 794 706 745 904 916 Cost(y) 75.85 61.52 108.73 99.58 71.79 119.22 108.78 112.85 141.52 138.08 Click to Copy-and-Paste Data A student calculates a linear model y = to two decimal places) X + (Please show your answers Use the model above to estimate the cost when number of pages is 503 Cost = $ places.) (Please show your answer to 2 decimalData in Appendix B compares the volumes of the contents of cans of Coke with the volumes of the contents of cans of Pepsi. See the information obtained below. Use a 0.05 significance level to test the claim that cans of Coke and Pepsi have the same mean weight. State the claim, state the claim in symbols, find the Null and alternative hypothesis, find the test statistic, find the critical value graph, find the critical values, find the decision, and what is the final conclusion. Coke ?1 = 36 ?1 = 0.11 oz. ?̅̅1 = 12.19 oz. Pepsi?2 = 36?̅̅2= 12.29 oz. ?2 = 0.09 oz.
- Application Exercise: Dr. Butler is interested in the preference for dog breeds among college students. She collected the observed frequencies below and wants to know if the breeds are equally preferred. What can be concluded with an a of 0.05? Irish Setter Golden Retriever Papillon Great Dane 101 94 135 97 L What is the appropriate test statistic? -Select Compute the statistic selected in : M Obtain/compute the appropriate values to make a decision about Hg. Critical Value = | J: Test Statistic = Decision: -Select- N Compute the corresponding effect size(s) and indicate magnitude(s). If not appropriate, input and/or select "na" below. Effect Size = | ]: Magnitude: -Select-- Make an interpretation based on the results. O There is a significant relationship between dog breeds and college students. There is a significant dog breed preference among college students. O Dog breeds are equally preferred among college students.Top quality 15% of the production is good quality, the worst 15% is bad quality, the rest are medium quality It is defined as. It is known that the production shows normal distribution with average and variance of 100. According to this; a) Below which yield level is poor quality valid? b) What yield levels is medium quality in? c) What level of efficiency is good quality called above?point) Four buses carrying 157 high school students arrive to Montreal. The buses carry, respectively, 33, 50, 25, and 49 students. One of the studetns is randomly selected. Let X denote the number of students that were on the bus carrying this randomly selected student. One of the 4 bus drivers is also randomly selected. Let Y denote the number of students on his bus. Compute the expectations and variances of X and Y: E(X) = Var(X) = E(Y) = Var(Y) =