A tank is full of water and the water is being pumped out of the spout (see figure). Use the fact that the density of water is 1000 kg/m³ and 9 = 9.8 m/s². (a) Find the work required to empty the tank. (b) Suppose that the pump breaks down after 705600 J of work has been done. Use the solve command to find the depth of the water remaining in the tank? + 2 m 3 m ↓ 8 m 3m →

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### Work Required to Empty a Water Tank

#### Problem Statement

A tank is full of water and the water is being pumped out of the spout (refer to the figure). Utilize the fact that the density of water is \( 1000 \, \text{kg/m}^3 \) and \( g = 9.8 \, \text{m/s}^2 \).

(a) Find the work required to empty the tank.

(b) Suppose that the pump breaks down after 705600 J of work has been done. Use the `solve` command to find the depth of the water remaining in the tank.

#### Diagram Description

The diagram provided shows a tank with the following dimensions:
- Length of the tank: \( 8 \, \text{m} \)
- Width of the tank: \( 3 \, \text{m} \)
- Depth from the bottom of the tank to the spout: \( 5 \, \text{m} \) (composed of 3 meters from the bottom of the tank to the water surface and an additional 2 meters to the spout)

#### Detailed Solution

Let’s break down the problem step-by-step.

1. **Calculate the Volume of a Thin Slice of Water:**
   - Assume a thin horizontal slice of water at a depth \( y \) from the bottom. The thickness of the slice is \( dy \).
   - The volume of the slice: \( dV = 8 \, \text{m} \times 3 \, \text{m} \times dy = 24\, dy \, \text{m}^3 \).

2. **Mass of the Slice:**
   - The mass \( dm \) of this thin slice of water: \( dm = \rho \, dV = 1000 \times 24 \, dy = 24000 \, dy \, \text{kg} \).

3. **Work to Lift a Slice to the Spout:**
   - The distance the slice needs to be lifted: \( 5 - y \, \text{meters} \).
   - Work \( dW \) to lift the slice: \( dW = dm \times g \times (5 - y) = 24000 \, dy \times 9.8 \times (5 - y) \).

4. **Integrate to Find the Total
Transcribed Image Text:### Work Required to Empty a Water Tank #### Problem Statement A tank is full of water and the water is being pumped out of the spout (refer to the figure). Utilize the fact that the density of water is \( 1000 \, \text{kg/m}^3 \) and \( g = 9.8 \, \text{m/s}^2 \). (a) Find the work required to empty the tank. (b) Suppose that the pump breaks down after 705600 J of work has been done. Use the `solve` command to find the depth of the water remaining in the tank. #### Diagram Description The diagram provided shows a tank with the following dimensions: - Length of the tank: \( 8 \, \text{m} \) - Width of the tank: \( 3 \, \text{m} \) - Depth from the bottom of the tank to the spout: \( 5 \, \text{m} \) (composed of 3 meters from the bottom of the tank to the water surface and an additional 2 meters to the spout) #### Detailed Solution Let’s break down the problem step-by-step. 1. **Calculate the Volume of a Thin Slice of Water:** - Assume a thin horizontal slice of water at a depth \( y \) from the bottom. The thickness of the slice is \( dy \). - The volume of the slice: \( dV = 8 \, \text{m} \times 3 \, \text{m} \times dy = 24\, dy \, \text{m}^3 \). 2. **Mass of the Slice:** - The mass \( dm \) of this thin slice of water: \( dm = \rho \, dV = 1000 \times 24 \, dy = 24000 \, dy \, \text{kg} \). 3. **Work to Lift a Slice to the Spout:** - The distance the slice needs to be lifted: \( 5 - y \, \text{meters} \). - Work \( dW \) to lift the slice: \( dW = dm \times g \times (5 - y) = 24000 \, dy \times 9.8 \times (5 - y) \). 4. **Integrate to Find the Total
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