A tank contains 1.85 moles of N2, 2.15 moles of Ne, 6.00 moles of Ar, and 4.00 moles of O2 at a total pressure of 1825.00 mm Hg. Complete the table below. N2 Ne Ar O2 Total Moles Given 14.00 mol X = Mole fraction 1.00 Partial pressure P = X¡Pr 1825.00 mm Hg

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Chapter1: Chemical Foundations
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What to do: Read the problem and solve for the missing values in the table below. Write
your answer in a separate sheet of paper.
A tank contains 1.85 moles of N2, 2.15 moles of Ne, 6.00 moles of Ar, and 4.00
moles of O2 at a total pressure of 1825.00 mm Hg. Complete the table below.
N2
Ne
Ar
O2
Total
Moles
Given
14.00 mol
Xị =
Mole fraction
1.00
Partial pressure
Pi = X;Pr
1825.00
mm Hg
Transcribed Image Text:What to do: Read the problem and solve for the missing values in the table below. Write your answer in a separate sheet of paper. A tank contains 1.85 moles of N2, 2.15 moles of Ne, 6.00 moles of Ar, and 4.00 moles of O2 at a total pressure of 1825.00 mm Hg. Complete the table below. N2 Ne Ar O2 Total Moles Given 14.00 mol Xị = Mole fraction 1.00 Partial pressure Pi = X;Pr 1825.00 mm Hg
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