A symmetrical parabolic vertical curve having length L=250 m, if the gradient of the two tangent g1= +1.5%,92= -1%, the elevation of the Vertex = (Zv) = 45.528 m,the (V) station =11+25.Compute: The elevation of the heights (lowest) point onthe curve.

Given Data: Length of curve is L=205 m. Gradient g1=1.5%. Gradient g2=-1%. Elevation of Vertex is…

A symmetrical parabolic vertical curve having length L =250 m, if the gradient of the two tangent g1= +1.5%, g2= -1%, the elevation of the Vertex = (Zv) = 45.528 m, the (V) station 11+25. Compute: The elevation of the heights (lowest) point on the curve.

A symmetrical parabolic vertical curve having length L =250 m, if the gradient of the two tangent g1= +1.5%, g2= -1%, the elevation of the Vertex = (Zv) = 45.528 m, the (V) station 11+25. Compute: The elevation of the heights (lowest) point on the curve.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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