A survey was conducted two years ago asking college students their top motivations for using a credit card. You think this distribution has changed.You randomly select 425 college students and ask each one what the top motivation is for using a credit card. Can you conclude that there has been achange in the distribution? Use a = 0.025. Complete parts (a) through (d).ResponseOld Survey %29%New Survey Frequency, fRewards110Low ratesCash backDiscounts23%9621%1097%46Other20%64O B. The distribution of motivations is 110 rewards, 96 low rate, 109 cash back, 46 discounts, and 64 other.O C. The distribution of motivations is 29% rewards, 23% low rate, 21% cash back, 7% discounts, and 20% other.Which hypothesis is the claim?o Ho(b) Determine the critical value, Yo, and the rejection region.X = 11.143 (Round to three decimal places as needed.)Choose the correct rejection region below.Oc. X

(c) The expected frequencies are calculated as,

Answered: A survey was conducted two years ago…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Polls. America OnLine published a survey question. Among the 2,300 Internet users who responded, 20% answered “yes” and the others answered “no.” For the “yes” responses, what is the value of pn? What is fundamen-tally wrong with this survey?
Medical Marijuana? An international poll of physicians was conducted on the New England Journal of Medicine website asking “Do you believe that the overall medicinal benefits of marijuana outweigh the risks and potential harms?” Identify the a. specified attribute. b. population. c. population proportion. d. Of the 1446 physicians who responded, 76% said yes. Is the proportion 0.76 (76%) a sample proportion or a population proportion? Explain your answer.
Given: I don’t understand how to compute the p-value below (problem 6): Sample size (n) = 12 Mean difference (Md) = 1.2 points SS = 33 Level of significance (a) = 0.05 Formula used: S d = √ S S n − 1 S d = S S n − 1 S E = S d √ n S E = S d n T h e t e s t s t a t i s t i c i s , t = M d S E Theteststatisticis, t= M d S E Here test statistic follows t-distribution with n-1 degrees of freedoms. Calculations: Here we have to test the hypothesis that, H0: μd =0 Vs H1: μd ≠ 0 Where μd is the population mean difference. S d = √ S S n − 1 = √ 33 12 − 1 = √ 33 11 = 1.73 S E = S d √ n = 1.73 √ 12 = 0.50 T h e t e s t s t a t i s t i c i s , t = M d S E = 1.2 0.5 = 2.4 Sd= S S n − 1 = 33 12 − 1 = 33 11 =1.73 SE= S d n = 1.73 12 =0.50 Theteststatisticis, t= M d S E = 1.2 0.5 =2.4 Test statistic (t) = 2.4 Degrees of freedom (df) = 12-1 =11 Now we have to find P-value By using statistical table of t-distribution we get: P-value = 0.0352 P-value < a Reject H0 at 5%…
During a season, the 40th percentile for points scored per player in a game is eight. Interpret the 40th percentile in the context of this situation. Forty percent of players scored 8 points or Sixty percent of players scored 8 points or more less
A study was done to look at the relationship between number of lovers college students have had in their lifetimes and their GPAs. The results of the survey are shown below. Lovers 4 8 3 7 0 6 5 6 GPA 2.7 2.3 3.4 2.4 3.5 2.9 2.7 2.8 r2r2 = (Round to two decimal places) Interpret r2r2 : There is a large variation in students' GPAs, but if you only look at students who have had a fixed number of lovers, this variation on average is reduced by 80%. Given any group of students who have all had the same number of lovers, 80% of all of these studetns will have the predicted GPA. 80% of all students will have the average GPA. There is a 80% chance that the regression line will be a good predictor for GPA based on the number of lovers a student has had. The equation of the linear regression line is: ˆyy^ = + xx (Please show your answers to two decimal places) Use the model to predict the GPA of a college student who as had 7 lovers.GPA = (Please round your…
CURSED MOVIE Released in 1956, the movie The Conqueror attracted considerable attention because many members of the cast and crew died from cancer supposedly resulting from exposure to radioactive fallout. The movie was shot a short distance from a site in Nevada where above-ground tests of atomic weapons were conducted. Among the 220 cast and crew members, 91 developed cancer. According to the National Cancer Institute, for that time period and for the age cohort, the incidence of cancer was about 40%. Use a 0.05 significance level to test the claim that the sample of cast and crew members is from a population in which the rate of cancer is greater than 40%. What do you conclude about the movie being a curse? Find null hypothesis and alternative hypothesis. Find test statsistic. Find P-value. How do you find p hat
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You are testing the claim that the proportion of men who own cats is larger than the proportion of women who own cats.You sample 160 men, and 15% own cats.You sample 60 women, and 20% own cats.Find the test statistic
Critical Values=
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You are testing the claim that the proportion of men who own cats is larger than the proportion of women who own cats.You sample 180 men, and 75% own cats.You sample 100 women, and 60% own cats.Find the test statistic.

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