A survey was conducted to calculate the average height students at MNSU. It turnsout that after asking every single student, the average height is 67.5 inches. Supposejust a few days before you obtained this mean, you took a sample of 200 studentsand constructed a confidence interval estimate of the average mean. Which of thefollowing is true?O The center of the interval will be 67.5O The interval will contain 67.5O The confidence level used was 99%O The z-score used for this interval is + 1.96None of the above

Answered: A survey was conducted to calculate the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
Give one method to increase statistical power and Which test statistic should you use if you are comparing two variances?
A 90% confidence interval for a population mean is (10, 20). What is the margin of error of the interval?
If n=31, (x-bar)=36, and S3D3, construct a confidence interval at a 95% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place.
You want to get a 90% confidence interval for the difference between the percentage of females with red hair compared to males with red hair. You sample 76 females and find 34 of them have red hair. You sample 65 males and find 33 have red hair. < p1−p2 <
The mean score on the math portion of the ACT for the year 2000 is μ = 20.7. A sample of 20 students in a local school district had a mean of 22.95. Using the sample, a 95% confidence interval estimate for the mean is (20.76, 25.14). State the point estimate for the mean ACT score for students. Based on this sample information , do you believe that the local students have a mean different from the general population? Why? 22.95 is in the center of the interval. The means are definitely not different. 22.95 is just outside the 95% confidence interval. Can't say the means are really different. 22.95 is not equal to 20.7. The means are definitely different. 20.7 is just outside the 95% confidence interval. Can't say the means are really different.
A researcher investigated whether the temperature of milk, x, can be used to predict the milk's pH content, y. She predicted the pH level of a glass of milk with a temperature of 8.45 degrees to be ŷ= 6.795 a)A 95% confidence interval for the mean pH of all milk with temperature 8.45 degrees is calculated to be (6.76, 6.83). Which of the following is the correct interpretation of this confidence interval? -The mean pH level for all glasses of milk having a temperature of 8.45 degrees is somewhere between 6.76 and 6.83, with 95% confidence. -The pH level for one glass of milk with a temperature of 8.45 degrees is somewhere between 6.76 and 6.83, with 95% confidence. -There is a probability of 0.95 that the mean pH level for this glass of milk with temperature 8.45 degrees is between 6.76 and 6.83. -95% of all glasses of milk with a temperature of 8.45 degrees have a pH level between 6.76 and 6.83. b)Suppose we have a glass of milk whose temperature is 8.45 degrees. We…
QUESTION 4 Sara wants to determine the mean play time of media clips on her smartphone. A random sample of 36 media clips revealed a mean of 155 minutes and a standard deviation of 16 minutes. Find the upper confidence limit (UCL) of the 93% confidence interval estimate for the mean play time of media clips on Sara's smartphone. Round your answer to two decimal places.
Find z* for a confidence level of 83%. Give your answer to 3 decimal places.
In a sample of 190 adults, 133 had children. Construct a 90% confidence interval for the true population proportion of adults with children.
Albert, a student of statistics, considered a random sample of the duration of 100 phone calls. He constructed the confidence interval with 95% confidence. Veronica selected her own random sample of 100 phone calls and constructed a confidence interval with 95% confidence. Is it possible that the confidence interval she obtained is different from the one Albert obtained? Explain why or why not. Suppose that they do not have information about the standard deviation of the population
From a sample of 500 Pepperdine students, 205 said they commuted to school. Find the 95% confidence interval using 2 decimal places for the proportion of Pepperdine students who commute. If you use a calculator, indicate the function used and the parameters you entered for the function.

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