### Public Opinion on 'Sin Taxes' on Soda and Junk FoodA survey conducted in March 2011 questioned 1000 adults in the US about their stance on 'sin taxes' on soda and junk food. The survey specifically asked, "Do you favor or oppose 'sin taxes' on soda and junk food?" The findings revealed that 32% of the respondents were in favor of taxing these types of foods. > "32% favor ‘sin taxes’ on soda, junk food”, Rasmussen Reports, April 1, 2011.### Statistical Analysis**(a) 90% Confidence Interval Calculation:**To determine the confidence interval for the proportion of US adults who favor taxes on soda and junk food, follow these steps:1. **Identify the sample proportion (p):** - Proportion (p) = 0.322. **Determine the standard error (SE) using the formula:** - SE = sqrt [ p(1 - p) / n ] - Where n is the sample size (1000 adults)3. **Calculate the margin of error (ME) for a 90% confidence level:** - For a 90% confidence level, the z-value (z*) is approximately 1.645. - ME = z* * SE4. **Construct the confidence interval:** - Lower limit = p - ME - Upper limit = p + ME**Compute the confidence interval and round the results to three decimal places:**The 90% confidence interval is \(\_\_\_\) to \(\_\_\_\).

Confidence interval is a type of estimate computed from the statistics of the observed data. This…

A survey of 1000 adults in the US conducted in March 2011 asked "Do you favor or oppose 'sin taxes' on soda and junk food?" The proportion in favor of taxing these foods was 32 %.1 "32% favor 'sin taxes' on soda, junk food", Rasmussen Reports, April 1, 2011. (a) Find a 90% confidence interval for the proportion of US adults favoring taxes on soda and junk food. Round your answers to three decimal places. The 90% confidence interval is to

A survey of 1000 adults in the US conducted in March 2011 asked "Do you favor or oppose 'sin taxes' on soda and junk food?" The proportion in favor of taxing these foods was 32 %.1 "32% favor 'sin taxes' on soda, junk food", Rasmussen Reports, April 1, 2011. (a) Find a 90% confidence interval for the proportion of US adults favoring taxes on soda and junk food. Round your answers to three decimal places. The 90% confidence interval is to

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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19.
Suppose that you are interested in the number of people in each household in the U.S. Your sample includes 10 households, with a mean 2.5 and a standard deviation 1.2. Construct a 95% confidence interval (CI) of the mean number of household members. (A) 1.2-3.8 (B) 1.4-3.6 (C)1.6-3.4 (D) 1.7-3.3 (E) 1.8-3.2
1- You want to construct a 99% confidence interval for the proportion of retail stores that went out of business due to the recent pandemic. You managed to collect a random sample of 93 retail stores and found 15% of them shut down permanently. Construct and interpret the confidence interval.
What is the conclusion? What is your conclusion? -There is no evidence to suggest a difference. -There is a difference in newborns' APGAR score based on whether the mother smoked or not. -Newborns whose mothers didn't smoke have higher APGAR score than newborns whose mother did smoke. -Newborns whose mothers didn't smoke have lower APGAR score than newborns whose mother did smoke.
Please help with A and B
8. In late 2020, a poll was conducted to determine the proportion of American adults that subscribed to a TV or movie streaming service since January 2020. The surveyors randomly selected 2200 American adults. The results are shown in the relative frequency table below. Response Frequency Subscribed to at least one 794 Did not subscribe to a new one 1406 Given this information, we want to create a 95% confidence interval to estimate the proportion of American adults that subscribed to a TV or movie streaming service since January 2020. a. What is the value of the point estimate for our 95% confidence interval? b. What is the margin of error for our 95% confidence interval? (Use the formula to compute it). Round your answer to three decimal places. C. Using your answers to parts (a) and (b), find a 95% confidence interval estimating the proportion of American adults that subscribed to a TV or movie streaming service since January 2020.
9.
11.
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