(a) Suppose that you can observe data that are independently and identically distributed as N(μ, 1).Your prior distribution for μ is N(m, v). After observing n₁ data with sample mean ₁, find yourposterior distribution for μ. You now observe a second sample of size n2 and with mean 2. Deriveyour new posteriori. by sequentially using the new data to update the posterior you obtained from the first sample,andii. by using all the data to update your original prior.Confirm that these two approaches yield the same answer.

Answered: (a) Suppose that you can observe data…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The null hypothesis: H. :|| The alternative hypothesis: H :0 1 The type of test statistic: (Choose one) v The value of the test statistic: (Round to at least three decimal places.) The p-value: (Round to at least three decimal places.) Can we reject the researchers' claim that the mean recovery time when treated with multivitamin is less than or equal to the mean recovery time when treated with vitamin C only? Yes No
For 50 randomly selected speed dates, attractiveness ratings by males of their female date partners (x) are recorded along with the attractiveness ratings by females of their male date partners (y); the ratings range from 1 to 10. The 50 paired ratings yield x= 6.4, y = 6.0, r= - 0.267, P-value = 0.061, and y= 7.90- 0.296x. Find the best predicted value of y (attractiveness rating by female of male) for a date in which the attractiveness rating by the male of the female is x= 4. Use a 0.01 significance level. The best predicted value of y when x= 4 is. (Round to one decimal place as needed.)
The height of corn stalks (in cm) have a N(μ1,σ1) distribution, while the height of Nebraska corn stalks have a N(μ2,σ2) distribution. It is known that σ1 ̸= σ2. A random sample of corn stalks from Iowa and Nebraska yielded the following summary statistics. Iowa: n1 =15 x ̄1 =155 s1 =16 Nebraska: n2 =17 x ̄2 =145 s2 =10 Suppose we wish to test H0 : μ1 = μ2 versus Ha : μ1 ̸= μ2 at the α = 0.10 significance level. What is the value of the test statistic (TS) and critical value (CV )? TS=2.09, CV=1.697 TS=2.09, CV=1.645 TS=2.15, CV=1.697 TS=2.15, CV=1.717 TS=2.15, CV=1.645 TS=2.09, CV=1.717
This column contains data x1, . . . , xn, which is assumed to be a sample from a normal distribution N(µ, σ 2 ). For this sample, find the maximum likelihood estimates µˆ and σˆ.
For 50 randomly selected speed dates, attractiveness ratings by males of their female date partners (x) are recorded along with the attractiveness ratings by females of their male date partners (y); the ratings range from 1 to 10. The 50 paired ratings yield x = 6.4, y = 5.9, r= - 0.319, P-value = 0.024, and y = 8.29 – 0.379x. Find the best predicted value of y (attractiveness rating by female of male) for a date in which the attractiveness rating by the male of the female is x = 8. Use a 0.10 significance level. ..... The best predicted value of y when x= 8 is (Round to one decimal place as needed.)
please answer part d only asap using R and show the R code. will give you good feedback
A food manufacturer claims that eating its new cereal as part of a daily diet lowers total blood cholesterol levels. The table shows the total blood cholesterol levels (in milligrams per deciliter of blood) of seven patients before eating the cereal and after one year of eating the cereal as part of their diets. Use technology to test the mean difference. Assume the samples are random and dependent, and the population is normally distributed. At α=0.05, can you conclude that the new cereal lowers total blood cholesterol levels? Patient 1 2 3 4 5 6 7 Total Blood Cholesterol (Before) 215 225 235 240 255 260 225 Total Blood Cholesterol (After) 214 222 240 237 254 257 222 Let the blood cholesterol level before eating the cereal be population 1. Let the blood cholesterol level after eating the cereal be population 2. Identify the null and alternative hypotheses, where μd=μ1−μ2. Choose the correct…
For 50 randomly selected speed dates, attractiveness ratings by males of their female date partners (x) are recorded along with the attractiveness ratings by females of their male date partners (y); the ratings range from 1 to 10. The 50 paired ratings yield x=6.4, y= 6.0, r= -0.124, P-value = 0.391, and y = 6.95-0.146x. Find the best predicted value of y (attractiveness rating by female of male) for a date in which the attractiveness rating by the male of the female is x = 7. Use a 0.10 significance level. The best predicted value of y when x 7 is. (Round to one decimal place as needed.)
The two assets, X and Y, whose returns are shown in the multivariate distribution to the right, have the following expected returns, variances, covariance, and correlation: mX = 13.00%; mY = 12.50%; sX = 3.317%; sY = 2.500%; Cov(X,Y) = -.0004; rXY = -.45 a) What is the expected return and standard deviation of a portfolio that is 50% Asset X and 50% Asset Y? b) What is the expected return and standard deviation of a portfolio that is 75% Asset X and 25% Asset Y? c) Which of the preceding portfolios ((a) or (b)) is better? Why? show all work and formulas used in excel
Can you help me with this please! Thank you.

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