A study was conducted on the average commuting distance of students at College. The study found that the first sample of thirty students has an average commute of 23.1 miles with a sample standard deviation of 12.47 miles. The commuting mileages for a second sample of 30 students are below. c) Use the means and standard deviations from each data set to illustrate the standard deviation method of identifying outliers (d)  Find the five number summary for this sample and determine if there are any outliers. State the outlier values if they exist. Show your outlier calculations

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A study was conducted on the average commuting distance of students at College. The study found that the first sample of thirty students has an average commute of 23.1 miles with a sample standard deviation of 12.47 miles. The commuting mileages for a second sample of 30 students are below.

c) Use the means and standard deviations from each data set to illustrate the standard deviation method of identifying outliers
(d)  Find the five number summary for this sample and determine if there are any outliers. State the
outlier values if they exist. Show your outlier calculations
(e) Explain why the average for the second sample is a better representation of the population of students
commuting to College. Which statistic from above proves this is the better value?

2034202015/16/1931 (15
121815131
128 11 2010
7 13 13 327 4 6318246
Transcribed Image Text:2034202015/16/1931 (15 121815131 128 11 2010 7 13 13 327 4 6318246
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Step 1

Answer:

c)

Identifying outliers using standard deviation:X¯ ± 2*SD

Formula:

Mean=X¯ =Xin

Standard Deviation for Sample =Xi2-nX¯2n-1

Here, n=30

Calculation table:

X X^2
20 400
34 1156
20 400
20 400
15 225
16 256
19 361
3 9
1 1
15 225
12 144
18 324
15 225
13 169
1 1
12 144
8 64
11 121
20 400
10 100
7 49
13 169
13 169
32 1024
7 49
4 16
63 3969
18 324
24 576
6 36
X=470 X2=11506

X¯=47030=15.67

SD=11506-(30)*(15.67)230-1=4139.5329 = 11.95

Now,

lower bound = X¯-2*SD=15.67-2*11.95=-8.23

Upper bound =X¯+2*SD =15.67+2*11.95 =55.24

There is only outlier 63.

 

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