A study shows that 30 percent of children in a given developing country are malnourished. Using normal approximation, find the probabilities that in a random sample of 25 children from this region, the number of malnourished children is a. higher than 5; b. between 4 and 8.
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- Use a normal approximation to find the probability of the indicated number of voters. In this case, assume that 157 eligible voters aged 18-24 are randomly selected. Suppose a previous study showed that among eligible voters aged 18-24, 22% of them voted. Probability that fewer than 41 votedAccording to a candy company, packages of a certain candy contain 24% orange candies. Find the approximate probability that the random sample of 300 candies will contain 29% or more orange candies. Using a normal approximation, what is the probability that at least 29% of 300 randomly sampled candies will be orange?Hershey Kiss Weight in Oz. 1 Jason, a Quality Process Engineer for Hershey Chocolates, pulled 16 random kisses from production and recorded their weights as shown. Jason uses the production number for each kiss in production to ensure that all of the kisses in production have an equal chance of being selected in his random number generator. .1618 .1607 .1613 A: Calculate a point estimate, x, for the population mean, u. .1607 .1610 1611 1609 .1597 .1586 .1604 B: Construct and interpret a 95% CI (Confidence Interval) for u. .1607 (Hint: Use s from your calculator's descriptive statistics.) .1606 1611 .1620 .1610 .1609 C: Construct and interpret a 99% CI (Confidence Interval) for µ.
- In a survey of 175 females who recently completed high school, 76% were enrolled in college. In a survey of 150 males who recently completed high school, 72% were enrolled in college. At a = 0.05, can you reject the claim that there is no difference in the proportion of college enrollees between the two groups? Assume the random samples are independent. Complete parts (a) through (e). O A. Ho: P1 #P2 Ha: P1 = P2 O B. Ho: P1 P2 OF. Ho: P1 = P2 O D. Ho: P1 > P2 Ha: P1 SP2 Ha: P1 O B. z 1.96 O D.The 2006 Statistical Abstract of the United States reports on a survey that asked a national sample of 80,000 American households about pet ownership. Suppose (for now) that one-third of all American households own a pet cat. Still supposing that one-third of all American households own a pet cat, between what two values do you expect 95% of all sample proportions to fall?use a normal approximation to find the probability of the indicated number of voters. in the case, assume that 136 eligible voters aged 18-24 are randomly selected. suppose a previous study showed that among eligible voters aged 18-24, 22% of them voted. probability that exactly 36 voted.Nationally, about 11% of the total U.S. wheat crop is destroyed each year by hail.† An insurance company is studying wheat hail damage claims in a county in Colorado. A random sample of 16 claims in the county reported the percentage of their wheat lost to hail. 16 6 8 9 10 18 14 13 9 10 25 18 13 8 14 3 The sample mean is x = 12.1%. Let x be a random variable that represents the percentage of wheat crop in that county lost to hail. Assume that x has a normal distribution and σ = 5.0%. Do these data indicate that the percentage of wheat crop lost to hail in that county is different (either way) from the national mean of 11%? Use ? = 0.01. (a) What is the level of significance? Compute the z value of the sample test statistic. (Round your answer to two decimal places.)(c) Find (or estimate) the P-value. (Round your answer to four decimal places.)Determine whether carpeted rooms have more bacteria than uncarpeted rooms at the a = 0.05 level of significance. Normal probability plots indicate that the data are approximately normal and boxplots indicate that there are no outliers. State the null and alternative hypotheses. Let population 1 be carpeted rooms and population 2 be uncarpeted rooms. A. Ho: H1= H2 H1: H1> H2 B. Ho: H1 H2 c. Hoi H1= H2 H1: H1The proportion of items in a population that possess a specific attribute is known to be 0.25 a. If a simple random sample of size n=100 is selected and the proportion of items in the sample that contain the attribute of interest is 0.30, what is the sampling error b. Referring to part a, what is the probability that a sample size of 100 would have a sample proportion of 0.30 or less if the population proportion is 0.25Nationally, about 11% of the total U.S. wheat crop is destroyed each year by hail.† An insurance company is studying wheat hail damage claims in a county in Colorado. A random sample of 16 claims in the county reported the percentage of their wheat lost to hail. 15 7 7 13 13 20 13 12 5 10 26 22 13 7 11 3 The sample mean is x = 12.3%. Let x be a random variable that represents the percentage of wheat crop in that county lost to hail. Assume that x has a normal distribution and σ = 5.0%. Do these data indicate that the percentage of wheat crop lost to hail in that county is different (either way) from the national mean of 11%? Use α = 0.01. (a) What is the level of significance? Compute the z value of the sample test statistic. (Round your answer to two decimal places.)(c) Find (or estimate) the P-value. (Round your answer to four decimal places.)Use a normal approximation to find the probability of the indicated number of voters. In this case, assume that 131 eligible voters aged 18-24 are randomly selected. Suppose a previous study showed that among eligible voters aged 18-24, 22% of them voted. Probability that fewer than 32 votedA survey is conducted to determine if there is a difference in the proportion of students, parents, and teachers who volunteer at least once a month. To investigate, a random sample of 45 students, 25 parents, and 12 teachers was selected from a large high school. The data are displayed in the tables. Observed counts: Expected counts: The researcher would like to test these hypotheses: H0: There is no difference in the distribution of responses among these three populations.Ha: There is a difference in the distribution of responses among these three populations. The conditions for inference are met. What is the value of the chi-square test statistic and what are the degrees of freedom for this test? χ‑2 = 0.19, df = 2χ‑2 = 0.19, df = 5χ‑2 = 0.44, df = 2χ‑2 = 0.44, df = 5SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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