A study investigated survival rates for in-hospital patients who suffered cardiac arrest. Among 60,000 patients who had cardiac arrest during the day, 11,610 survived and were discharged. Among 28,500 patients who suffered cardiac arrest at night, 5400 survived and were discharged. Use a 0.01 significance level to test the claim that survival rates are the same for day and night patients. a) Define the parameters and state null and alternative hypothesis b) Test Statistics c) P-value Approach d) Conclusion

Q: A random sample of 860 births in New york state included 434 girls. Use a 0.05 significance level to…

A: The aim is to test the claim that 48.8% of newborn babies are girls. The test hypotheses are given…

Q: A statistics student believes that black cars are less likely to receive tickets for moving…

A: It is given that the P-value is 0.24.

Q: According to the Center for Disease Control website, in 2011 more than 18% of high school students…

A: It is given that 150 students surveyed, 82 have smoked.

Q: A simple random sample of size n 200 drivers with a valid driver's license is asked if they drive an…

A: Solution: Given information:  n= 200 Sample size of drivers  x = 122 drivers drive an American made…

Q: We would like to compare the proportions of Notre Dame Seniors who choose to live off-campus by…

A: The claim of the test is to test whether the proportion of seniors living off-campus is…

Q: Assume significance level of a=-.05: In a recent study of a random sample of 113 people, 92 reported…

A: The following information has been provided: n=113x=92 p=0.29

Q: According to a union agreement, the mean income for all senior-level workers in a large service…

A: From the provided information, Sample size (n) = 9 Sample mean (x̄) = 410 Standard deviation (s) =…

Q: A study was conducted of 531 persons injured in bicycle crashes. The subjects were asked if they…

A: Claim ; there was a relationship between helmet wearing and the occurrence of facial injuries.

Q: The null hypothesis for ANOVA states that a. the variables are independent b. the variables are…

A: ANOVA: In one factor ANOVA model only one factor is studied, that is only the effect on one factor…

Q: A labor statistician claims that 6% of the labor forces will be laid off likely  to pandemic impact.…

A: Solution: Let X be the number of employees will be likely to be laid off and n be the sample number…

Q: Based on past experience, a hiring manager believes that less than one-third of applicants are…

A:

Q: Past studies have indicated that the percentage of smokers was estimated to be about 34%. Given the…

A:

Q: A health organization asserts that the prevalence of smoking among male adults 18 years or older in…

A: The test hypotheses are: Null hypothesis: H0: p1 = p2 Alternative hypothesis: Ha: p1 > p2. Test…

Q: A researcher examines whether a majority of individuals prefer to wear their seat belts when driving…

A: Hypothesis testing is an act in statistics whereby an analyst tests an assumption regarding a…

Q: A new study shows that 35% of adults have never been married. To test if that is a true claim, we…

A: Given: n= 250.0 ,x= 97.0 p= 0.35 ,significance level(∝)= 0.05p̂= 97.0 / 250.0 =0.388

Q: 1. This is an example of a 2. Find the standard error. 3. Find the z value. -- hypothesis test.

A: Given,To find the type of test, standard error, and calculate the z value.

Q: According to a geographic report, in the United States, 20% of all families renting condos will move…

A:

Q: A  simple random sample of size n = 200 drivers with a valid driver's license is asked if they drive…

A: The answer to the question :  "Do you drive an American-made automobile?" is either  "Yes" or "No"…

Q: cording to a survey, the average American person is in a car for 5 hours per week. To test if the…

A:

Q: A national publishing house claims that 35% of all weekly magazine readers inSouth Africa read their…

A: Null Hypothesis: H0: The proportion of all weekly magazine readers in South Africa read their…

Q: In a study of smokers who tried to quit smoking with nicotine patch therapy, 39 were smoking after…

A: Given Information: The number of smokers who tried to quit smoking with nicotine patch therapy,…

Q: In a random sample of soldiers who fought in the Battle of Preston, 774 soldiers were from the New…

A: The hypotheses are given below: Null hypothesis: H0:p=0.25 Alternative hypothesis: H1:p>0.25 The…

Q: Researchers wish to test whether marijuana use among full-time college students aged 19-22 at a…

A: 1) The appropriate Null and Alternative Hypotheses are given below: From the given information, the…

Q: A simple random sample of size n= 200 drivers with a valid driver's license is asked if they drive…

A:

Q: est the hypothesis that the proportion of airplane accidents due to pilot error is not 0.51. Use a…

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Q: The bad debt ratio for a financial institution is defined to be the dollar value of loans defaulted…

A: The data of mean bad debt ratio of 65 banks are given and objective is to test whether the mean bad…

Q: A study was conducted to determine the proportion of people who dream in black and white instead of…

A: The random variable X follows binomial distribution. We have to use normal approximation to binomial…

Q: A random sample of Americans were categorized according to their happiness and their income level.…

A: H0: Income and Happiness are independent HA: Income and Happiness are dependent

Q: A food company claims a population mean of 625 calories in their frozen lasagna entrées. A sample of…

A:

Q: An insurance company collects data on seat-belt use among drivers in a country. Of 1600 drivers…

A:

Q: USA Today article claims that the proportion of people who believe global warming is a serious issue…

A: Given that  Sample size n =20 Favorable cases x =12 Sample proportion p^=x/n  =12/20 =0.60

Q: Rhinoviruses typically cause common colds. In a test of the effectiveness of​ echinacea, 41of the 47…

A: From the given information, let Xl be the number of subjects effective while they are treated with…

Q: USA Today (Feb. 17, 2011) described a survey of 1,008 American adults. One question on the survey…

A: a) The sample proportion is p-cap = 205/1008           = 0.203 b) The population proportion p is…

Q: A statistics student asked students with jobs how many times they went out to eat in the last week.…

A: Solution

Q: Researchers designed a survey to compare the proportions of children who come to school without…

A:

Q: According to the Center of Disease Control and Prevention (CDC), 18% of adults in the U.S. over 19…

A: The p-value is 0.0073.

Q: A study was conducted to determine the proportion of people who dream in black and white instead of…

A:

Q: A study was conducted to determine the proportion of people who dream in black and white instead of…

A:

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.