A student's grade in a certain course is modeled by the joint PDF below; where X is the grade of the lecture component, and Y is the grade of the lab component. 6 0
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- For the data shown to the right, determine the linear correlation coefficient using two different formulas shown below. Complete parts (a) and (b) below and compare your answers. x 1|2| 4 | 5|5 y 3 5 1 1 2 Exy - (Ex)(E) in b. Use the computing formula r= E-(Ex)*/n] E-(Ex)° /n] Find the sums required to calculate r using the computing formula. Ex-D Σ- (Type integers or decimals. Do not round.) Using the computing formula, r= (Round to three decimal places as needed.) V the value in part (b). The value in part (a) is ?Pv. Don't provide handwriting solutionFind the mean and standard deviation for each uniform continuous model. (Round "Mean" answers to 1 decimal place and "Standard deviation" answers to 4 decimal places.) Mean Standard deviation a. U(2, 12) 7 b. U(100, 250) 175 c. U(2, 99) 50.5 know I need the standard deviation when I try to calculate it and enter my answer it says its wrong, need help
- Consider random variables X and Y with the joint PDF below find pxyConsider the distribution of lifetimes, X(in months) of a particular type of component. The CDF of X isB 1-e**** F(x) ,X > 0 a. Find the pdf of lifetime. b. Find the median of lifetime. c. Find the time t such that 10% of the components fail before t.gua-L8.5 CW.p X A Maya Paniagua - Copy of H X 5B"16VW7-mB9MvFajLes2zwUztrRR_ZFrd2e"%5D%2C"acti odf 100% 14 202 L1l.4 23 2045?=23 4. 5, 7. =180 38 mz1 = m25 = %3D %3D m22 = m26 = m23 = m27 = %3D m24 = m28 = %3D
- * Let E(X]Y = y) = 3y and var(X|Y = y) = 2, and let Y have the p. d. f. se-y if y > 0 fG) = {o otherwise Then the variance of X isFind the mean and standard deviation for each uniform continuous model.(Round "Mean" answers to 1 decimal place and "Standard deviation" answers to 4 decimal places. a. U(3,13)Let X be the total amount saved in dollars at the cash register. The pdf of X is given by: Value of X 20 28 40 50 58 70 probability 0.36 0.21 0.24 0.1225 0.0175 0.03 .0175 0.0025 Before I make the purchase, you would place my chance of saving $20 at 24%. Suppose you approach me after I pay for my items and ask: "Did you save any money?" If I answer "no", then you know I didn't save $20 and thus the chance of saving $20 changes from the unconditional chance 24% to the conditional chance 0%. However, if I answer "yes" my chance of saving $20 would get higher. What would be the conditional chance of saving $20 if you knew I got a discount? Mathematically, we seek: P(X = 20|X > 0 ). Even though it looks weird, it is just a conditional probability. Find it. P(X = 20|X > 0) = P(X = 20 and X > 0) / P(X > 0) = Hint: P(X = 20 and X > 0) be read off the table by identifying possible values where the event (X = 20 and X > 0) is true, don't use the multiplication rule. Do not round, express your…