A student was tasked to recover the crystals after recrystallization. He weighed a piece of filter paper and found its weight to be 0.9843 g. After filtration, he weighed the same filter paper again and found its weight to be 1.718 g. What is the mass of the crystals recovered?

A student was tasked to recover the crystals after recrystallization. He weighed a piece of filter paper and found its weight to be 0.9843 g. After filtration, he weighed the same filter paper again and found its weight to be 1.718 g. What is the mass of the crystals recovered?

Chemistry & Chemical Reactivity

10th Edition

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter11: Intermolecular Forces And Liquids

Section11.6: Properties Of Liquids

Problem 1.2ACP

See similar textbooks

Similar questions

2. The goal behind suction filtration is to remove soluble impurities that are on the surface of the crystals. Therefore, why can't you simply use suction filtration instead of recrystallization to purify an impure solid?
0.3414 grams of sample (crushed aspirin tablet) was weighed and dissolved in 25 mL ethanol. This solution was transferred into a 100 mL volumetric flask and filled to the mark with deionized water. 20 mL of the solution was filtered through a 0.22 μm pore filter and 503 μL of the filtered sample solution was diluted so, that the final volume of the solution was 12 mL. This sample solution and calibration solutions with known concentration of acetyl salicylic acid (ASA) were injected (injection volume 20 μL) into a HPLC and the following peak areas were measured (expressed as averages from three separate chromatographic runs): Solution Cal 1 Cal 2 Cal 3 Cal 4 Cal 5 Sample Structure of ASA: C(ASA) (mg/L) 0 OH B 53.5 105.9 140.9 195.4 247.4 Average weight of the tablet was estimated as 591.9 mg. What is the mass of ASA in one tablet? Please give the answer with 4 significant digits. Be sure you present the result with units! Peak area (mA.s) 4995 9953 12941 17271 22179 10467.3
A 25.0 ml aliquot of a well-shaken and filtered sample of river water is pipetted into an evaporating dish. The sample was heated to dryness. Determine the concentration of Total Dissolved Solids (TDS) in mg/L given the following data: Mass of evaporating dish = 25.5 g Mass of dried sample plus evaporating dish = 25.9729 g Note: Round off your answer to the nearest whole number.
A student is recrystallizing 2.034 g of acetylsalicylic acid (aspirin) that was isolated from 8.00 grams of Excedrin. The recrystallization requires a seed crystal to begin. The seed crystal weighs 0.389 g. The student's actual yield after recrystallization is 1.663 g. What is the percent recovery?
It is a type of mixture with particles evenly scattered in a dispersed medium without settling down
Weigh out accurately 9.99 g of copper(II) sulfate pentahydrate (CuSO4·5H2O) by taring using a clean and dry empty 250-ml beaker. 2. Add tap water to the beaker to reach the 50-mL mark on the side of the beaker. 3. Dissolve all the crystals of CuSO4·5H2O in the water using a clean glass rod for stirring. 4. Then using a glass funnel transfer all the blue solution to a 100-mL volumetric flask. Rinse the beaker with about 10 mL of water and transfer the solution to the volumetric flask. Repeat the rinsing of the beaker with another 10 mL of water and transfer the solution to the volumetric flask. This is called quantitative transfer of the solution. 5. Then add enough water to reach the calibration mark of the volumetric flask. (You will need to use a dropper to add the last few drops of water to ensure the meniscus is on the calibration mark). Close the volumetric flask with a stopper and mix the solution well (so that it is homogeneous). 6. You have now prepared a standard solution (or…
Porosity is a measure of the void or empty spaces in a material and is a fraction of the volume of voids over the total volume. The density of the solid material used to create 13 pieces of 0.6 cm diameter and 0.67 cm height cylindrical beads is determined to be 1.53 g/mL. These beads were then placed in a flask and was filled to the 42 mL mark with a salt solution. The total weight measured of the beads and the salt solution was 51.68 g. Upon further inspection, it was found that manufacturing defects caused the measured porosity of the beads to be at 21%. Assuming that the solution was able to fully fill the empty spaces inside the beads, calculate the density of the salt solution. Show your solutions in the next item Round your answer to 2 decimal places. Add your answer
Q3: In a chromatographic analysis, a solution was prepared with 0.0837 M Octane (A) and 0.0666 M nonane (B). Each one produced a peak area of AA = 423 and AB = 347.10.0 ml of 0.146 M nonane was added to 10 ml of an unknown sample, and the sample diluted to 25 ml. The peak areas obtained were AA = 553 and AB = 582. What is the concentration of Octane in the unknown sample?
QUESTION 16 Match the correct choices with the given. For gravimetric analysis, use this data to answer the questions. |Trial 1 0.6020 g 24.8405 g 24.8451 g 24.8422 Trial 2 0.5021 g 22.8165 g 22.8165 g Trial 3 0.5018 g 22.8169 g 22.8169 g |Weight of Sample Weight of Crucible and Ba$O, 8 24.8422 g Constant Weight of Crucible & Sample 24.8422 g 22.8165 g 22.8169 g Weight of Crucible 24.3181 22.3593 g 22.3641 g 24.3160 g 24.3142 g 24.3142 g 24.3142 g 24.3142 g 22.3523 g 22.3534 g 22.3532 g 22.3532 g 22.3612 g 22.3605 g 22.3605 g 22.3605 g Constant Weight of Crucible 22.3532 g 22.3605 g Weight of BaSo, |% so,2- Average Standard deviation Relative standard deviation A. 2.65 Average of the % (w/w) SO42- B. to decompose the solid and form a compound of known composition and to remove the solvent and any non-volatile species Standard deviation of the % (w/w) So2- Relative standard deviation of the C. reprecipitation % (w/w) SO42- D. formation of small crystals This is a drastic but effective…
a sample of sodium carbonate Na2CO3 is being dried. after 1 hour of drying the mass of the sample was 0.337g. after an additional 30 minutes of drying the mass of the sample is 0.333g what is the percent change between the first and second measurement? if to be considered dry two consecutive measurements must have a percent change of less than or equal to plus or minus 1% is the sample dry?
3.A core sample is saturated with an oil (po = 35°API), gas and water. The initial weight of the sample is 224.14 g. After the gas is displaced by water (pw = 1 g/cm'), the weight is increased to 225.90 g. The sample is the placed in a Soxhlet distillation apparatus, and 4.4 cm' water is extracted. After drying the core sample, the weight is now 209.75 g. The sample bulk volume, 95 cm3 is measured in a mercury pycnometer. Find the porosity, water saturation, oil saturation, gas saturation and lithology of the core sample.
Can someone answer number 2 please