A student was asked to find a 95% confidence interval for the population proportion of students who take notes using data from a random sample of size n-87. Which of the following is a correct interpretation of the interval 0.13
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- A teacher would like to estimate the mean number of steps students take during the school day. To do so, she selects a random sample of 50 students and gives each one a pedometer at the beginning of the school day. They wear the pedometers all day and then return them to her at the end of the school day. From this, she computes the 98% confidence interval for the true mean number of steps students take during the school day to be 8,500 to 10,200 steps. Which of these statements is a correct interpretation of the confidence level? A) Approximately 98% of students take between 8,500 and 10,200 steps per day. B) The teacher can be 98% confident that the interval from 8,500 to 10,200 captures the true mean number of steps taken by students during the school day. C) If many random samples of size 50 are selected from all students at this school, approximately 98% of the intervals would capture the true mean number of steps taken during the school day. D) Approximately 98% of the…From a random sample of 120 students, 95 rated a case of plagiarism as unethical. Using this information, you computed a confidence interval extending from 0.68 to 0.76 for the population proportion. What is the confidence coefficient of the interval?A student was asked to find a 90% confidence interval for the population proportion of students who take notes using data from a random sample of size n = 81. Which of the following is a correct interpretation of the interval 0.14 < p < 0.26? Check all that are correct. There is a 90% chance that the proportion of notetakers in a sample of 81 students will be between 0.14 and 0.26. With 90% confidence, a randomly selected student takes notes in a proportion of their classes that is between 0.14 and 0.26. There is a 90% chance that the proportion of the population is between 0.14 and 0.26. The proprtion of all students who take notes is between 0.14 and 0.26, 90% of the time. With 90% confidence, the proportion of all students who take notes is between 0.14 and 0.26.
- A student was asked to find a 98% confidence interval for the proportion of students who take notes using data from a random sample of size n = 86. Which of the following is a correct interpretation of the interval 0.11 < p < 0.33? Check all that are correct. The proportion of all students who take notes is between 0.11 and 0.33, 98% of the time. With 98% confidence, a randomly selected student takes notes in a proportion of their classes that is between 0.11 and 0.33. There is a 98% chance that the proportion of the population is between 0.11 and 0.33. There is a 98% chance that the proportion of notetakers in a sample of 86 students will be between 0.11 and 0.33. With 98% confidence, the proportion of all students who take notes is between 0.11 and 0.33.A researcher reports t(5) = +3.00, p < .05 for a repeated-measures research study. The mean sample difference score for the sample was MD = 12. Which of the following is the confidence interval for the population mean difference?A student was asked to find a 99% confidence interval for the proportion of students who take notes using data from a random sample of size n = 75. Which of the following is a correct interpretation of the confidence interval, 0.15 < p < 0.2? Check all that are correct. O With 99% confidence, the proportion of All students who take notes is between 0.15 and 0.2. O There is a 99% chance that the proportion of notetakers in a sample of 75 students will be between 0.15 and 0.2. O With 99% confidence, a randomly selected student takes notes in a proportion of their classes that is between 0.15 and 0.2. Question Help: Message instructor Submit Question H Q a
- In a random sample of 63, the proportion of the sample with a certain characteristic was 0.61. What is the 95% confidence interval for pp?A random sample of 21 lunch orders at Noodles & Company showed a mean bill of $13.54 with a standard deviation of $6.45. Find the 98 percent confidence interval for the mean bill of all lunch orders. (Round your answers to 4 decimal places.) The 98% confidence interval is from _____to______A student was asked to find a 90% confidence interval for the proportion of students who take notes using data from a random sample of size n = 86. Which of the following is a correct interpretation of the confidence interval, 0.12 < p < 0.25? Check all that are correct. There is a 90% chance that the proportion of notetakers in a sample of 86 students will be between 0.12 and 0.25. With 90% confidence, a randomly selected student takes notes in a proportion of their classes that is between 0.12 and 0.25. With 90% confidence, the proportion of All students who take notes is between 0.12 and 0.25.
- A student was asked to find a 90% confidence interval for widget width using data from a random sample of size n = 20. Which of the following is a correct interpretation of the interval (11.5,21.6)? There is a 90% chance that the mean of a sample of 20 widgets will be between 11.5 and 21.6. The mean width of all widgets is between 11.5 and 21.6, 90% of the time. We know this is true because the mean of our sample is between 11.5 and 21.6. With 90% confidence, the mean width of a randomly selected widget will be between 11.5 and 21.6. We are 90% confident the mean width of all widgets is between 11.5 and 21.6. There is a 90% chance that the mean of the population is between 11.5 and 21.6.A music manager wanted to construct a 95% confidence interval for the lenght of songs produced at his recording studio. Using data from a random sample of 47 songs, he obtained an interval of 3.05 < μ < 4.45. Which of the following is the correct interpretation of the interval? With 95% confidence, the mean width of all widgets is between 3.05 and 4.45. The mean width of all widgets is between 3.05 and 4.45, 95% of the time. We know this is true because the mean of our sample is between 3.05 and 4.45. There is a 95% chance that the mean of the population is between 3.05 and 4.45. With 95% confidence, the mean width of a randomly selected widget will be between 3.05 and 4.45. There is a 95% chance that the mean of a sample of 47 widgets will be between 3.05 and 4.45.In a survey of 31 students at a local high school, 15 support changing the school's mascot. Find the 95% confidence interval for the true population proportion of students who support changing school's mascot.Choose the correct confidence interval and critical value used in the calculation. A. (0.254,0.714) (Zc=2.576) B. (0.304,0.664)(Zc=1.96) C. (0.304,0.664)(tc=2.0423) D. 0.334,0.634)(Zc=1.645) E. (0.274,0.694) (Zc=2.326)