A student took a random sample of 159 properties to examine how much more waterfront property is worth. Her summaries and boxplots of the two groups of prices are shown. Construct and interpret a 90% confidence interval for the mean additional amount that waterfront property is worth. 800- Non-Waterfront Prop. Waterfront Prop. 600- 92 67 400 233,905.76 336,463.97 159,927.11 102,348.74 200- NW W The 90% confidence interval is (Round to the nearest whole number as needed.) Interpret the confidence interval. O A. We're 90% confident that a waterfront property is worth $65,613 to $139,503 more. O B. We're 90% confident that a waterfront property is worth $65,613 to $139,503 less. O C. We're 90% confident that houses are worth between $65,613 to $139,503. Sale Prices ($1000)

A student took a random sample of 159 properties to examine how much more waterfront property is worth. Her summaries and boxplots of the two groups of prices are shown. Construct and interpret a 90% confidence interval for the mean additional amount that waterfront property is worth. 800- Non-Waterfront Prop. Waterfront Prop. 600- 92 67 400 233,905.76 336,463.97 159,927.11 102,348.74 200- NW W The 90% confidence interval is (Round to the nearest whole number as needed.) Interpret the confidence interval. O A. We're 90% confident that a waterfront property is worth $65,613 to $139,503 more. O B. We're 90% confident that a waterfront property is worth $65,613 to $139,503 less. O C. We're 90% confident that houses are worth between $65,613 to $139,503. Sale Prices ($1000)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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I sampled 10 downtown Chicago restaurants for the price of their most expensive meal on the menu. Here are the prices: $45, $80, $70, $70, $60, $65, $80, $60, $50, $90 Construct a 99% confidence interval for the mean price of the most expensive meal at a downtown Chicago restaurant. Assume the population is approximately normal. Write a sentence using that confidence interval Using the values in the previous question, compute a 95% confidence interval for the standard deviation of the most expensive price for a mean in downtown Chicago.
Portland State University (PSU) reported that 64% of their students receive financial aid. A PSU administrator feels that their school may have a different proportion compared to all of Oregon schools. A random sample of 409 students in Oregon found that 259 receive financial aid. Test the claim that proportion of students that receive financial aid in Oregon is different than PSU. Use a 1% significance level. Give answer to at least 4 decimal places. a. What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.) Ho: Select an answer ?v H₁: Select an answer ? ✓ Based on the hypotheses, compute the following: b. Test Statistic = c. p-value = d. Based on the above we choose to Select an answer e. The correct summary would be: Select an answer that the proportion of students that receive financial aid in Oregon is different than the PSU reported value of 64%.
24. Job Interviews In a Harris poll of 514 human resource professionals, 90% said that the appearance of a job applicant is most important for a good first impression. a. Among the 514 human resource professionals who were surveyed, how many of them said that the appearance of a job applicant is most important for a good first impression? b. Construct a 99% confidence interval estimate of the proportion of all human resource professionals believing that the appearance of a job applicant is most important for a good first impression. c. Repeat part (b) using a confidence level of 80%. d. Compare the confidence intervals from parts (b) and (c) and identify the interval that is wider. Why is it wider?
The National Association of Colleges and Employers sponsors the Graduating Student and Alumni Survey.Part of the survey gauges student optimism in landing a job after graduation. According to one year’s surveyresults, published in American Demographics, among the 1218 respondents, 733 said that they expecteddifficulty finding a job. Construct a 90% confidence interval for the proportion of students who expecteddifficulty finding a job. Interpret your result.
A political scientist claims that 38% of first-year college students characterize themselves as being “moderate” or “middle of the road” as far as their political affiliation is concerned. Believing this claimed value is too high, you survey a random sample of 400 first-year college students and find that 120 characterize themselves as being “moderate” or “middle of the road.” Based on this information, what will the test statistic be? Choose the answer below that is closest to what you calculate, and try not to do a lot of rounding until you get to the very end of your calculations. 1. -0.3 2. -1.2 3. -2.6 4. -3.3 5. None of the other answer options are correct because the test statistic should be positive, not negative.
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Create an Excel spreadsheet. Conduct an independent sample t-test evaluating if cat owners or dog owners love their pet more. Ratings for cat owners- 7,6,5,9,5 Ratings for dog owners- 8,7,9,10 Write APA formatted results for thus analysis, including Cohen's d for the results and a bar graph with Error Bars showing 95 percent confidence intervals.
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Several studies showed that after eating a low-fat cereal for two meals a day, subjects had lost some weight.A cereal companyfinanced this research. Identify what is wrong. Choose the correct answer below. A. Since the research is composed of voluntary response samples, there may be key data points missing. B. The data used in the studies is not reliable because it was not measured by the administrator. C. It is questionable that the sponsor is a cereal company because this sponsor can be greatly affected by the conclusion. D. It is not possible to take accurate measurements.
An online retailer has identified the maximum willingness of 10 consumers to pay for the same product. The 10 prices are: $10.00, $11.50, $9.50, $10.20, $11.20, $10.50, $9.80, $10.10, $9.90, $11.00 The retailer seeks a 95% confidence interval for the mean price consumers are willing to pay. The sample mean is calculated as $10.37, and the sample standard deviation is $0.66. Also consider the following t-values: Degrees of freedom 8 a. (9.99, 10.75) 9 10 90% confidence 1.86 1.833 1.812 95% confidence 2.306 2.262 2.228 99% confidence 3.355 3.250 3.169 Selecting the correct t-value, calculate the limits of the confidence interval.
A researcher investigates whether single people who own pets are generally happier than singlepeople without pets. A group of non-pet owners is compared to pet owners using a mood inventory.The pet owners are matched one to one with the non-pet owners for income, number of closefriendships, and general health. A. Single-sample z-testB. Single-sample t-testC. Independent samples t-testD. Related samples t-test (repeated measures or matched samples)E. Correlation