A student prepares phosphorous acid by reacting solid phosphorous triiodide with water PI₃(s) + 3 H₂O(l) → H₃PO₃(s) + 3 HI(g) The student needs to obtain 0.359 L of phosphorous acid (d=1.651g/mL). The procedure calls for a 43.3 % excess of water and a yield of 70.8%. How much phosphorous triiodide should be weighed out?
A student prepares phosphorous acid by reacting solid phosphorous triiodide with water PI₃(s) + 3 H₂O(l) → H₃PO₃(s) + 3 HI(g) The student needs to obtain 0.359 L of phosphorous acid (d=1.651g/mL). The procedure calls for a 43.3 % excess of water and a yield of 70.8%. How much phosphorous triiodide should be weighed out?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A student prepares phosphorous acid by reacting solid phosphorous triiodide with water
PI₃(s) + 3 H₂O(l) → H₃PO₃(s) + 3 HI(g)
The student needs to obtain 0.359 L of phosphorous acid (d=1.651g/mL). The procedure calls for a 43.3 % excess of water and a yield of 70.8%. How much phosphorous triiodide should be weighed out?
Expert Solution
Step 1
The given equation is:
volume of phosphorous acid = 0.359 L= 359 mL
density of phosphorous acid = 1.651 gram/ mL
so,
Molar mass of phosphorous acid = 82 gram/mole
Then, determine the number of moles by dividing the mass by its molar mass.
so,
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