A student needs to prepare a buffer solution with a pH of 4.85. Assuming a pK₂ of 4.31, how many mL of 0.1 M NaOH would need to be added to 19.0 mL of 0.1 M HB to prepare this buffer? Please include a proper (abbreviated) unit. HINT: Use pH = pK₂ + log ([B minus]/[HB]) or, if concentrations are the same, pH = pk₂ + log (Volume of OH minus/ (Volume of HB minus Volume of OH minus)

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A student needs to prepare a buffer solution with a pH of 4.85. Assuming a pK₂ of 4.31, how many mL of
0.1 M NaOH would need to be added to 19.0 mL of 0.1 M HB to prepare this buffer?
Please include a proper (abbreviated) unit.
HINT: Use pH = pka + log ([B minus]/[HB]) or, if concentrations are the same,
pH = pka + log (Volume of OH minus/ (Volume of HB minus Volume of OH minus)
Transcribed Image Text:A student needs to prepare a buffer solution with a pH of 4.85. Assuming a pK₂ of 4.31, how many mL of 0.1 M NaOH would need to be added to 19.0 mL of 0.1 M HB to prepare this buffer? Please include a proper (abbreviated) unit. HINT: Use pH = pka + log ([B minus]/[HB]) or, if concentrations are the same, pH = pka + log (Volume of OH minus/ (Volume of HB minus Volume of OH minus)
Expert Solution
Step 1: Introduction to buffer solution

In the given question we have to calculate the volume of NaOH used to make the buffer solution.

buffer solution is the mixture of weak acid and its salt solution which resists the change in pH of the solution when little amount of acid or base added to solution. We have to use henderson hasselbalch equation to calculate the volume of NaOH.

Given:

pH = 4.85

pKa = 4.31

Concentration of NaOH = 0.1 M

Concentration of HB = 0.1 M

Volume of HB = 19.0 mL


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