A student kicks a football vertically upwards with a speed of 20.0m/s. Determine all unknowns and answer the following questions. Neglect drag and the initial height and horizontal motion of the football. What was the football's maximum height? unit What was the football's total flight time? unit

A student kicks a football vertically upwards with a speed of 20.0m/s. Determine all unknowns and answer the following questions. Neglect drag and the initial height and horizontal motion of the football. What was the football's maximum height? unit What was the football's total flight time? unit

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A student fires a cannonball vertically upwards with a speed of 39.0m/s. Determine all unknowns and answer the following questions. Neglect drag and the initial height and horizontal motion of the cannonball. What was the cannonball's maximum height? unit How long did the cannonball rise? unit What was the cannonball's total flight time? unit check answers cannot be de Unit 12: forces and motion review, one-dimensional motion problems Desmos Scientific Online Calculator
A major leaguer hits a baseball so that it leaves the bat at a speed of 30 m/s at an angle of 36.9° above the horizontal. The bat is at a height of 1.2 m when it hits the baseball. Ignore air resistance. What is the time of flight of the baseball? - 8) a) b) What is the maximum height of the baseball? What is the horizontal distance the baseball flies? What are the components of the velocity of the baseball just before it lands on the ground? e) What is the final magnitude and direction of the baseball? d)
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Solve the problem. PROVIDE THE GIVEN, REQUIRED, EQUATION, SOLUTION, AND FINAL ANSWER Troy throws a ball horizontally from a height of 8.50 m with an initial speed of 37.0 m/s. a) How long will it take the ball to reach the ground? b) At what horizontal distance from the point of release will it strike the ground?
1. The distance between home plate and the pitcher's mound in baseball is 60.5 ft. In MLB, baseballs are. pitched at about 90mph. Assume the ball is thrown perfectly horizontally, at 0°. How far in feet will the ball drop during its transit to home plate? Use g = 32 ft/s². (Note: this is why pitcher's mounds are raised.) 2. A pebble is tossed into the air at an angle of 62° above the horizontal, with an initial speed of 4.8 m/s. The pebble is 1.6m above the ground when it is released by the thrower's hand. a) How long will the pebble remain airborne? b) What maximum height above the ground will the pebble achieve?
In lab you roll a marble off the edge of your table, and it goes flying through the air until it hits the floor 2.0 m out on the floor from below the launch point. (That's distance along the floor from just below where the marble became airborne to the point on the floor where it landed.) The table is level, so the marble is moving horizontally when it first becomes airborne. If the marble exited the table at 4.0 m/s … i) How long was the marble airborne?
6. A skilled golfer hits a ball so that it just clears the top of a tree and onto an elevated green as shown. The tree is horizontally a distance, x = 18.3 m from the golfer and its height is 10.2 m. a) Determine the golf ball's initial y-velocity so that the maximum height it reaches is the same as the height of the tree. b) Determine the time it takes for the ball to climb to that maximum height c) Using the time information in b, determine the golf ball's initial x-velocity d) Using your answer to a) and c), determine the magnitude and direction of the golf ball's initial velocity. e) If the golfer was to hit the ball over level ground so that it went as far as possible, at what angle would he want to hit the ball? Explain.
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Problem In a relief operation mission involving a helicopter h distance above the ground traveling with a horizontal velocity vx. What should be the expression for the horizontal distance dx at which you release the relief package so that it will arrive to the survivors at the right place? (Neglect the effect of air resistance) Solution To determine this, we must first derive the time it takes for the relief package to reach the survivors. We use this equation -h = vinitial-yt + (1/2)ay________________ If we just drop the package from the helicopter, the equation above becomes ________________=________________ + (1/2)ay_____________________ Substituting ay = -g then simplifying results to t = sqrt( _____________/______________ ) which is the time it takes for the object to reach the ground. Since the package will just travel at a constant velocity in the x-axis, thus dx = vxt Substituting the time taken by the package to reach to ground results to: dx = ( _________ )( sqrt…
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4. A ball is projected with an initial upward velocity component of 80 ft/sec and a horizontal velocity component of 100 ft/sec. a) Find the position and velocity of the ball after 2sec, 3 sec and 6 sec. b) How long a time is required to reach the highest point of trajectory? c) How high is this point? d) How long a time is required for the ball to return to its original level? e) How far has it traveled horizontally during this tme. Show your results in a neat sketch to show all features cearly.
Problem In a relief operation mission involving a helicopter h distance above the ground traveling with a horizontal velocity vy. What should be the expression for the horizontal distance dy at which you release the relief package so that it will arrive to the survivors at the right place? (Neglect the effect of air resistance) Solution To determine this, we must first derive the time it takes for the relief package to reach the survivors. We use this equation -h = Vinitial-ył + (1/2)ay %3D If we just drop the package from the helicopter, the equation above becomes + (1/2)ay %3D Substituting ay =-g then simplifying results to t = sqrt( which is the time it takes for the object to reach the ground. Since the package will just travel at a constant velocity in the x-axis, thus dx = Vxt Substituting the time taken by the package to reach to ground results to: dx = ( )( sqrt ( which is the expression for the horizontal distance at which you should drop the package.