A student gets his car stuck in a snow drift. Not at a loss, having studied physics, he attaches one end of a stout rope to the vehicle and the other end to the trunk of a nearby tree, allowing for a small amount of slack. The student then exerts a force on the center of the rope in the direction perpendicular to the car-tree line, as shown in the figure below. If the rope is inextensible and if the magnitude of the applied force is 483 N, what is the force on the car? (Assume equilibrium conditions.) kN 12 m Tree 0.50 m
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- of Three forces are applied to a bracket as shown. Point A lies at the origin of the xy-axes. F1 = 250 N, F2 = 500 N and F3 =375 N F2 F1 30°f 0.5 m 0.5 m 1 y A B 0.5 m -0.5 m Moment MA = F3 a) Replace the system by an equivalent force-couple system at A. Resultant Force Component in x direction= Resultant Force Component in y direction= 0.3 m- YR measured from A= N.m N b) Determine where the equivalent single force line of action intersects the y-axis measured from A. m NOn the way to Hilton Head, S.C. for Spring Break, your car breaks down in the middle of nowhere. A tow truck weighing 4500 lbs comes along and agrees to tow your car, which weighs 1800 lbs, to the nearest town. The driver of the truck attaches his cable to your car at an angle of 22° from the horizontal. He tells you that his cable has a strength of 550 lbs. He plans to take 10 seconds to tow your car at a constant acceleration from rest, in a straight line along the flat road, until he reaches the maximum speed limit of 45 miles/hour. Can the driver carry out his plan? You assume that rolling friction behaves like kinetic friction, and the coefficient of rolling friction between your tires and the road is 0.10.Problem: A block is resting on a ramp as shown in the figure below. You can change the inclination angle θ by raising one end of the ramp. The block has a mass mb=6.5 kg. At the interface between the ramp and the block, the coefficient of static friction is μs=0.4, and the coefficient of kinetic friction is μk=0.28. I managed to calculate that: slip angle is θ= 21.8 degrees acceleration is 1.09 m/s^2. I am trying to find: Let the angle θ be the angle you calculated , θslip (21.8 degrees) . To keep the block from slipping, you apply a horizontal (parallel to the surface of Earth) force directed to the right on the block. Your horizontal force F→Yb has a magnitude of 45 N. Calculate the magnitude and direction of the force due to static friction for this new situation, assuming that the block does not slip. Enter a magnitude for this part, but consider what the sign of your answer tells you about the direction of the force.
- A system comprised blocks, a light frictionless pulley, and connecting ropes is shown in the figure. The B block has a mass of 9.5 kg and is on a perfectly smooth horizontal table. The surfaces of the A block, which has a mass of 10.5 kg, are rough, with µ = 0.31 between the block and the table. If the C block with mass 7.2 kg accelerates downward when it is released, find its acceleration. A C.Please find the magnitude of t1 answer for magnitude of t2 = 672 What is the magnitude of t3 ?A person is pushing a wheelbarrow along a ramp that makes an angle ?=43.0∘ with the horizontal. The wheelbarrow and load have a combined mass of ?=24.05 kg with the center of mass at the midpoint of the length ?. What is the magnitude of the net force ?net that the person must apply in order to push the wheelbarrow up the ramp at a constant velocity, while keeping the wheelbarrow in a level, horizontal orientation? Assume that the radius of the wheel is small enough to ignore. Use ?=9.81 m/s2.
- Box m₁ = 2.4 kg remains stacked on box m₂ = 15.9 kg as they are pulled from rest across a smooth, horizontal floor by a constant horizontal force of magnitude P = 24.4 N, as in the figure. What is the magnitude Fnet of the net force on the upper box? net m1 m2 = P NThe light right-angle boom which supports the 450-kg cylinder is supported by three cables and a ball-and-socket joint at O attached to the vertical x-y surface. Determine the reactions at O and the cable tensions. y 1.65 m! 1.70 m C 1.40 m E 1.40 m A 2.80 m 0.85 m B 0.85 m 450 kg Answers: Ox = i N Oy = i N O2 = i N TẠC = i N TBD = i N TBE = i NCreate a FBD for segment 1 that is attached to the lower end of the cord. Assume, for the moment, that the weight is in equilibrium. Given: Enumerate the segments as i=1,⋯,N from the lower to the upper end. Let T0 be the tension at the lower end of the cord. Let Ti be the tension at the upper end of segment i. Let Fg,M be the weight of the mass on the end of the cord. Let Fg,i be the weight of segment i of the cord.
- As shown in the figure, a climber with a weight of 533.8 N is held by a belay rope connected to her climbing harness and belay device; the force of the rope on her has a line of action through her center of mass. The indicated angles are 0 = 40.0° and = 30.0°. If her feet are on the verge of sliding on the vertical wall, what is the coefficient of static friction between her climbing shoes and the wall?USE VECTOR NOTATIONIn a physics laboratory class, three massless strings are tied together at a point. A tensile force is applied along each rope: F_1 = 150 N at 60°, F_2 = 200. N at 100°. F_3 = 100. N at 190° What is the magnitude of a fourth force and the angle at which it acts to keep the point at the center of the system stationary? (All angles are measured from the positive x-axis counterclockwise.)A block is resting on a ramp as shown in the figure below. You can change the inclination angle θ by raising one end of the ramp. The block has a mass mb = 8.5 kg. At the interface between the ramp and the block, the coefficient of static friction is μs = 0.450, and the coefficient of kinetic friction is μk = 0.270.If you raise the end of the ramp very slowly, at what angle will it slip?