A student dissolves 20. g of benzoic acid (C,H,0,) in 125. mL of a solvent with a density of 1.07 g/mL. The student notices that the volume of the solvent does not change when the benzoic acid dissolves in it. Calculate the molarity and molality of the student's solution. Be sure each of your answer entries has the correct number of significant digits. molarity = molality %3D olo
A student dissolves 20. g of benzoic acid (C,H,0,) in 125. mL of a solvent with a density of 1.07 g/mL. The student notices that the volume of the solvent does not change when the benzoic acid dissolves in it. Calculate the molarity and molality of the student's solution. Be sure each of your answer entries has the correct number of significant digits. molarity = molality %3D olo
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Details
1. **Given Data:**
- **Mass of benzoic acid:** 20.0 g
- **Volume of solvent:** 125. mL
- **Density of solvent:** 1.07 g/mL
2. **Molar Mass Calculation:**
- **Molar mass of benzoic acid (C\(_7\)H\(_6\)O\(_2\)):**
- Carbon (C): 12.01 g/mol
- Hydrogen (H): 1.01 g/mol
- Oxygen (O): 16.00 g/mol
Formula: C\(_7\)H\(_6\)O\(_2\)
- Molar mass = (7 × 12.01) + (6 × 1.01) + (2 × 16.00)
- Molar mass = 84.07 + 6.06 + 32.00 = 122.13 g/mol
3. **Molarity Calculation:**
- **Volume of solution in liters:** 125 mL = 0.125 L
- **Moles of benzoic acid:**
- Moles = Mass / Molar mass = 20.0 g / 122.13 g/mol = 0.164 mol
- **Molarity (M):**
- Molarity = Moles / Volume = 0.164 mol / 0.125 L = 1.31 M
4. **Molality Calculation:**
- **Mass of solvent in grams:**](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F688553c1-a29d-4d73-a765-adb59e2cd2b6%2Fefe7fc22-91ad-4009-9674-9b8a00b0f336%2Fiqh75dr_processed.png&w=3840&q=75)
Transcribed Image Text:### Problem Statement
A student dissolves 20.0 g of benzoic acid (C\(_7\)H\(_6\)O\(_2\)) in 125. mL of a solvent with a density of 1.07 g/mL. The student notices that the volume of the solvent does not change when the benzoic acid dissolves in it.
**Task:** Calculate the molarity and molality of the student's solution. Ensure each of your answer entries has the correct number of significant digits.

### Details
1. **Given Data:**
- **Mass of benzoic acid:** 20.0 g
- **Volume of solvent:** 125. mL
- **Density of solvent:** 1.07 g/mL
2. **Molar Mass Calculation:**
- **Molar mass of benzoic acid (C\(_7\)H\(_6\)O\(_2\)):**
- Carbon (C): 12.01 g/mol
- Hydrogen (H): 1.01 g/mol
- Oxygen (O): 16.00 g/mol
Formula: C\(_7\)H\(_6\)O\(_2\)
- Molar mass = (7 × 12.01) + (6 × 1.01) + (2 × 16.00)
- Molar mass = 84.07 + 6.06 + 32.00 = 122.13 g/mol
3. **Molarity Calculation:**
- **Volume of solution in liters:** 125 mL = 0.125 L
- **Moles of benzoic acid:**
- Moles = Mass / Molar mass = 20.0 g / 122.13 g/mol = 0.164 mol
- **Molarity (M):**
- Molarity = Moles / Volume = 0.164 mol / 0.125 L = 1.31 M
4. **Molality Calculation:**
- **Mass of solvent in grams:**
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