A student determines the value of the equilibrium constant to be 3.93x1013 for the following reaction. 4HCI(g) + O2(g)–2H,0(g) + 2Cl,(9) Based on this value of Keg than zero. AG° for this reaction is expected to be (greater, less) Calculate the free energy change for the reaction of 2.36 moles of HCI(g) at standard conditions at 298K. kJ AG rxn =

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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A student determines the value of the equilibrium constant to be 3.93x1013 for the following reaction.
4HCI(g) + O2(g)
-2H,0(g) + 2Cl,(g)
Based on this value of Keg:
AG° for this reaction is expected to be (greater, less)
than zero.
Calculate the free energy change for the reaction of 2.36 moles of HCI(g) at standard conditions at 298K.
AG°rxn =
kJ
OC 8PWOO
MacBook Pro
71
F8
Transcribed Image Text:A student determines the value of the equilibrium constant to be 3.93x1013 for the following reaction. 4HCI(g) + O2(g) -2H,0(g) + 2Cl,(g) Based on this value of Keg: AG° for this reaction is expected to be (greater, less) than zero. Calculate the free energy change for the reaction of 2.36 moles of HCI(g) at standard conditions at 298K. AG°rxn = kJ OC 8PWOO MacBook Pro 71 F8
ccess Important values If needed for this question.
For the reaction
Fe,0,(s) + 4H,(g)-
3Fe(s) +4H,0(g)
AH° = 151 kJ and AS° = 169 J/K
AG° for this reaction would be negative at temperatures (above, below)
K.
Enter above or below in the first box and enter the temperature in the second box. Assume that AH° and AS° are constant.
OC8PWGO
MacBook Pro
Transcribed Image Text:ccess Important values If needed for this question. For the reaction Fe,0,(s) + 4H,(g)- 3Fe(s) +4H,0(g) AH° = 151 kJ and AS° = 169 J/K AG° for this reaction would be negative at temperatures (above, below) K. Enter above or below in the first box and enter the temperature in the second box. Assume that AH° and AS° are constant. OC8PWGO MacBook Pro
Expert Solution
Step 1

 At equilibrium the reaction spontaneous or non spontaneous that depends on the value of ∆G° of the reaction.

      We can calculate ∆G° of the reaction by using the formula

    ∆G°rxn = -2.303×RT log Keq

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