edofA student concludes, based on the density curve shown below,that the probability of a value of 45 is between .04 and .05.What is wrong with this student's conclusion?0.080.07-0.06-0.05-0.040.03-0.020.01-0.0030Select one:C.35An40OCT445505560a. nothing; this student is correctO b. the probability of a value of 45 is obtained by lookingat the area under the curve to the left of 45the values on the y axis are not probabilitiesClear my choice65tv70?2 dlMacBook Air

Based on the density curve, the student concludes that the probability of obtaining the value 45 is…

Answered: A student concludes, based on the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Let X = {Email, In Person, Instant Message, Text Message}; P(Email) = 0.06 P(In Person) = 0.55 P(Instant Message) = 0.24 P(Text Message) = 0.15 Is this model a probability distribution? A. Yes. B. No. C. Maybe.
Let x be the number of potential weapons detected by a metal detector at an airport on a given day. The following table lists the probability distribution of x. P(x) 0 .14 1 28 2 22 3 .18 .12 5 .06 Calculate the mean and standard deviation for this probability distribution and give a brief interpretation of the value of the mean.
The probability that a standard normal variable, Z, lies between 0 and 1.96 is: O A. 0.450 O B. 0.950 O C. 0.475 O D. 0.500 E. 0.900
Suppose the random variable Z follows a standard normal distribution. Then the probability is 0.20 that Z is less than the value O a. 0.84 O b. -0.84 O c. - 0.80 Od. 0.80
For a standard normal distribution, determine the probabilities in parts a through d below. page 1 of the standard normal probability table. Second digit of z First digit of z 0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 -3 0.0013 0.0013 0.0013 0.0012 0.0012 0.0011 0.0011 0.0011 0.001 0.001 -2.9 0.0019 0.0018 0.0018 0.0017 0.0016 0.0016 0.0015 0.0015 0.0014 0.0014 -2.8 0.0026 0.0025 0.0024 0.0023 0.0023 0.0022 0.0021 0.0021 0.002 0.0019 -2.7 0.0035 0.0034 0.0033 0.0032 0.0031 0.003 0.0029 0.0028 0.0027 0.0026 -2.6 0.0047 0.0045 0.0044 0.0043 0.0041 0.004 0.0039 0.0038 0.0037 0.0036 -2.5 0.0062 0.006 0.0059 0.0057 0.0055 0.0054 0.0052 0.0051 0.0049 0.0048 -2.4 0.0082 0.008 0.0078 0.0075 0.0073 0.0071 0.0069 0.0068 0.0066 0.0064 -2.3 0.0107 0.0104 0.0102 0.0099 0.0096 0.0094 0.0091 0.0089 0.0087 0.0084 -2.2 0.0139 0.0136 0.0132 0.0129 0.0125 0.0122 0.0119 0.0116 0.0113 0.011 -2.1 0.0179 0.0174 0.017 0.0166 0.0162 0.0158 0.0154 0.015…
Assume you have a normal distribution. What is the probability of obtaining a z greater than the following?: +1.645 +2.322 -0.407 -7.091 +0.950
Let z be a standard normal random variable with mean ? = 0 and standard deviation ? = 1. Use Table 3 in Appendix I to find the probability. (Round your answer to four decimal places.) To the left of 1.3
Suppose the random variable Z follows a standard normal distribution. Then the probability is 0.67 that Z is greater than the number A 0.63 B 0.44- C 0.63- D 0.44
If z is a standard normal variable, find the probability. P(Z < 0.97) O 0.1660 0.8340 O 0.8078 0.8315
A normal distribution with a mean of O and a standard deviation of 1 is called O a probability density function. O a standard normal distribution. O an ordinary normal curve. none of the other statements is correct.

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A student concludes, based on the density curve shown below, that the probability of a value of 45 is between .04 and .05. What is wrong with this student's conclusion? 0.08- 0.07 0.06- 0.05- 0.04- 0.03 0.02- 0.01 0.00 30 35 40 45 50 55 60 65 70