A structural engineer finished a design of a library. They determine that each column will carry 1000 lbs. the soil beneath the footing has the properties: gamma= 130 pcf, c= 75psf, phi= 40 degrees. The groundwater table is of great depth so it’s no concern. Sketch figures. What is the minimum size of the footing for a factor of safety of 3? Case 1: assume square footing Case 2: assume round footing

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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A structural engineer finished a design of a library. They determine that each column will carry 1000 lbs. the soil beneath the footing has the properties: gamma= 130 pcf, c= 75psf, phi= 40 degrees. The groundwater table is of great depth so it’s no concern. Sketch figures. What is the minimum size of the footing for a factor of safety of 3? Case 1: assume square footing Case 2: assume round footing
Case II: Assume round footing
No, No, N
1000
100
10
0.1
0
Na
10
N
20
o' (degrees)
30
0
40
50
Transcribed Image Text:Case II: Assume round footing No, No, N 1000 100 10 0.1 0 Na 10 N 20 o' (degrees) 30 0 40 50
Expert Solution
Step 1: Case 1- square footing:

To calculate the minimum footing size, we need to use the following equation:

qa = qu / FOS

where:

  • qa is the allowable bearing capacity (psf)
  • qu  is the ultimate bearing capacity (psf)
  • FOS is the factor of safety and (3)


The ultimate bearing capacity of a square footing can be calculated using the following equation:


qu = Nc * c + Nq * γ * D + Nγ * γ * Df

where,

  • Nc , Nq , Nγ are bearing capacity factors,

 which depend on the soil friction angle and the depth of the footing

  • c is the soil cohesion (psf)
  • γ is the soil unit weight (pcf)
  • D is the depth of the footing (ft)
  • Df is the depth to the groundwater table (ft)


Using the given soil properties and a bearing capacity factor chart, we can calculate the following bearing capacity factors:

Nc = 30

Nq = 20

Nγ = 0

Substituting these values,


qu = 30 * 75 + 20 * 130 * D

To calculate the allowable bearing capacity:


qa = (30 * 75 + 20 * 130 * D) / 3

1000 = (30 * 75 + 20 * 130 * D) / 3 

Solving this equation for D, we get:

D = 2.6 ft


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