A stretched-out Slinky spring is shaken rapidly (4 complete up-and-down shakes per second). A photograph reveals the wave crests are 0.72 meters apart. The ripple move along the Slinky with a velocity of meters/second. (use the equation shown below to help you calculate the answer) speed or velocity (ms ¹) v=fλ= frequency (Hz) 4.72 O 0.18 2.88 3.24 wavelength (m)

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Chapter1: Units, Trigonometry. And Vectors
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### Understanding Wave Motion in a Slinky Spring

In this lesson, we will explore the concept of wave motion using a stretched-out Slinky spring. Consider the following scenario:

A stretched-out Slinky spring is shaken rapidly, completing 4 up-and-down shakes every second. A photograph of the Slinky reveals that the distance between consecutive wave crests (the wavelength) is 0.72 meters. We want to determine the velocity of the wave moving along the Slinky.

#### Key Information:
- **Frequency (f)**: 4 Hz (4 shakes per second)
- **Wavelength (λ)**: 0.72 meters

#### Formula for Wave Velocity:
To calculate the wave velocity (v), we use the equation:

\[ v = f \lambda \]

Where:
- \( v \) is the speed or velocity of the wave (meters per second, ms⁻¹)
- \( f \) is the frequency (Hertz, Hz)
- \( \lambda \) is the wavelength (meters, m)

#### Diagram Explanation:
The provided diagram visually represents the formula \( v = f \lambda \) with arrows pointing to each variable:
- **Speed or Velocity (v)** is indicated in green (ms⁻¹).
- **Frequency (f)** is indicated in blue (Hz).
- **Wavelength (λ)** is indicated in red (meters, m).

#### Calculation:
By substituting the given values into the formula, we find:

\[ v = 4 \, \text{Hz} \times 0.72 \, \text{m} = 2.88 \, \text{ms}⁻¹ \]

Therefore, the velocity of the wave is **2.88 meters per second (ms⁻¹)**.

#### Multiple Choice Question:
The velocity of the wave is:
- \( \square \) 4.72
- \( \square \) 0.18
- \( \square \) 2.88 (Correct Answer)
- \( \square \) 3.24
Transcribed Image Text:### Understanding Wave Motion in a Slinky Spring In this lesson, we will explore the concept of wave motion using a stretched-out Slinky spring. Consider the following scenario: A stretched-out Slinky spring is shaken rapidly, completing 4 up-and-down shakes every second. A photograph of the Slinky reveals that the distance between consecutive wave crests (the wavelength) is 0.72 meters. We want to determine the velocity of the wave moving along the Slinky. #### Key Information: - **Frequency (f)**: 4 Hz (4 shakes per second) - **Wavelength (λ)**: 0.72 meters #### Formula for Wave Velocity: To calculate the wave velocity (v), we use the equation: \[ v = f \lambda \] Where: - \( v \) is the speed or velocity of the wave (meters per second, ms⁻¹) - \( f \) is the frequency (Hertz, Hz) - \( \lambda \) is the wavelength (meters, m) #### Diagram Explanation: The provided diagram visually represents the formula \( v = f \lambda \) with arrows pointing to each variable: - **Speed or Velocity (v)** is indicated in green (ms⁻¹). - **Frequency (f)** is indicated in blue (Hz). - **Wavelength (λ)** is indicated in red (meters, m). #### Calculation: By substituting the given values into the formula, we find: \[ v = 4 \, \text{Hz} \times 0.72 \, \text{m} = 2.88 \, \text{ms}⁻¹ \] Therefore, the velocity of the wave is **2.88 meters per second (ms⁻¹)**. #### Multiple Choice Question: The velocity of the wave is: - \( \square \) 4.72 - \( \square \) 0.18 - \( \square \) 2.88 (Correct Answer) - \( \square \) 3.24
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