The equation of a certain traveling transverse wave is y = 2 cos (200nt – 0.057x ) where x and y are in cm and t is the time in seconds. 18. Find the transverse velocity of the vibration in y-direction, as a function of time. Hint: Take the partial derivative with respect to t, treating x as a constant. a. Uy c. U, = -0.05 sin 2n(100t – 0.025x) = -400 r sin 2n(100t – 0.025x) b. U, = -200 sin 2r(100t – 0.025x) d. U, = -0. 10 r sin 2a(100t – 0.025x)

Physics for Scientists and Engineers: Foundations and Connections
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Chapter17: Traveling Waves
Section17.3: Harmonic Waves
Problem 17.3CE
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The equation of a certain traveling transverse wave is y = 2 cos (200nt – 0.057x ) where x and y are in cm and t is the
time in seconds.
18. Find the transverse velocity of the vibration in y-direction, as a function of time. Hint: Take the partial derivative with
respect to t, treating x as a constant.
a. Uy
c. U, = -0.05 sin 2n(100t – 0.025x)
= -400 r sin 2n(100t – 0.025x)
b. U, = -200 sin 2r(100t – 0.025x)
d. U, = -0. 10 r sin 2a(100t – 0.025x)
Transcribed Image Text:The equation of a certain traveling transverse wave is y = 2 cos (200nt – 0.057x ) where x and y are in cm and t is the time in seconds. 18. Find the transverse velocity of the vibration in y-direction, as a function of time. Hint: Take the partial derivative with respect to t, treating x as a constant. a. Uy c. U, = -0.05 sin 2n(100t – 0.025x) = -400 r sin 2n(100t – 0.025x) b. U, = -200 sin 2r(100t – 0.025x) d. U, = -0. 10 r sin 2a(100t – 0.025x)
Expert Solution
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Given data

The equation of the wave is: y1 = 2 Cos (200Πt – 0.05Πx)

 

 

The transverse velocity of the wave is found out by the partial derivative of the equation of wave with time. The expression for the transverse velocity is given as:

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