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A stop block, s, prevents a crate from sliding down a 0 = 23.0 ° incline. (Figure 1) A tensile force F = (Fot) N acts on the crate parallel to the incline, where Fo = 330 N/s. If the coefficients of static and kinetic friction between the crate and the incline are H, = 0.300 and Hk = 0.190, respectively, and the crate has a mass of 44.4 kg , how long will it take until the crate reaches a velocity of 4.25 m/s as it moves up the incline? Express your answer numerically in seconds to three significant figures. • View Available Hint(s) ΑΣφ It vec ?

A stop block, s, prevents a crate from sliding down a 0 = 23.0 ° incline. (Figure 1) A tensile force F = (Fot) N acts on the crate parallel to the incline, where Fo = 330 N/s. If the coefficients of static and kinetic friction between the crate and the incline are H, = 0.300 and Hk = 0.190, respectively, and the crate has a mass of 44.4 kg , how long will it take until the crate reaches a velocity of 4.25 m/s as it moves up the incline? Express your answer numerically in seconds to three significant figures. • View Available Hint(s) ΑΣφ It vec ?

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Learning Goal: To use the principle of linear impulse and momentum to relate a force on an object to the resulting velocity of the object at different times. The equation of motion for a particle of mass m can be written as dv EF = ma = m- dt By rearranging the terms and integrating, this equation becomes the principle of linear impulse and momentum: ΣFd S dv = m = mv2 – mv1 For problem-solving purposes, this principle is often rewritten as t2 mvị +£ F dt = mv2 The integral F dt is called the linear impulse, I, and the vector mv is called the particle's linear momentum. A stop block, s, prevents a crate from sliding down a 0 = 23.0 ° incline. (Figure 1) A tensile force F = (Ft) N acts on the crate parallel to the incline, where Fo = 330 N/s. If the coefficients of static and kinetic friction between the crate and the incline are ug = 0.300 and u = 0.190, respectively, and the crate has a mass of 44.4 kg, how long will it take until the crate reaches a velocity of 4.25 m/s as it moves up the incline? Express your answer numerically in seconds to three significant figures. • View Available Hint(s) vec ? t = S Submit
Transcribed Image Text:Learning Goal: To use the principle of linear impulse and momentum to relate a force on an object to the resulting velocity of the object at different times. The equation of motion for a particle of mass m can be written as dv EF = ma = m- dt By rearranging the terms and integrating, this equation becomes the principle of linear impulse and momentum: ΣFd S dv = m = mv2 – mv1 For problem-solving purposes, this principle is often rewritten as t2 mvị +£ F dt = mv2 The integral F dt is called the linear impulse, I, and the vector mv is called the particle's linear momentum. A stop block, s, prevents a crate from sliding down a 0 = 23.0 ° incline. (Figure 1) A tensile force F = (Ft) N acts on the crate parallel to the incline, where Fo = 330 N/s. If the coefficients of static and kinetic friction between the crate and the incline are ug = 0.300 and u = 0.190, respectively, and the crate has a mass of 44.4 kg, how long will it take until the crate reaches a velocity of 4.25 m/s as it moves up the incline? Express your answer numerically in seconds to three significant figures. • View Available Hint(s) vec ? t = S Submit
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