stone thrown from the top of a building is given an initial velocity of 20.0 m/s straight upward. The stone is launched 50.0 m above the ground, and the stone just misses the edge of the roof on its way down as shown in Figure 2.14. (A) Using l = 0 as the time the stone leaves the thrower's hand at position 0. determine the time at which the stone reaches its maxi- mum height. SOL LTIOL
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
![N Example 2.10
Not a Bad Throw for a Rookie!AM
V
Astone thrown from the top of a building is given an initial velocity
of 20.0 m/s straight upward. The stone is launched 50.0 m above the
ground, and the stone justI misses the edge of the roof on its way down
as shown in Figure 2.14.
t=
ye = 20.4 m
2.04 s
se--9.80 m/s
(A) Using la = 0 as the time the stone leaves the thrower's hand at
position O, determine the time at which the stone reaches its maxi-
mum height.
sa= 20.0 m/s
ae= -9.80 m/s
© le = 4.08 s
Ye= 0
e- -20.0 nm/s
e= -9.80 m/s?
SOLUTION
Ye
with dropping ohi-
nole 2.
) Posi n,
u OW-
veloe
aes ar
ing
"pwar and
a freely f ing ne
nes
p.
av
tity
Ma
ies
- ienc
10 simula
a the
sels r-
on
tin-
small e
er
I r val-
the
O la = 5.00 s
Ye- -22.5 m
",e= -29.0 m/s
4- -9.80 m/s2
sat
quir
50.0 m
bi-
of a' aildi
ie r
ston"
s ? art
der e
ion
*non
d
.oc is positi
wi chan si
i dal
ne ve c
tone
sint. F
1 ahvays
ar derati a of
have ner
e
= 5.83 s
0 = -50.0 m
",e= -37.1 m/s
Se= -9.80 m/s
de
nat it al a
e al
noose an
i ial
st after
- st
leaves 1e er
and a final
oint at th cop of i ight.
rime at whic
V = v. + a,1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe6733fcb-80a3-4fa2-84da-2c6e484b82f5%2Fff77b915-1008-4265-a035-db59346385cf%2F2g23xgo_processed.jpeg&w=3840&q=75)
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