• A stone is thrown horizontally at +17 m/s from the top of a cliff 40 m high. How long does the stone take to reach the bottom of the cliff? t = 2.86 s How far from the base of the cliff does the stone strike the ground? Sx = 48.62 m What is the speed of the stone just before it strikes the ground? |v| = 32.8 m/s 1 Sy = SAV + ‚ + (v₁)t − 1 / 8 gt S₂ = Sµ |v₁ = V, mat A ±(v₁ )t v¸ = V₁ – gt y A ► 17 m/s A (0,0) Sx
• A stone is thrown horizontally at +17 m/s from the top of a cliff 40 m high. How long does the stone take to reach the bottom of the cliff? t = 2.86 s How far from the base of the cliff does the stone strike the ground? Sx = 48.62 m What is the speed of the stone just before it strikes the ground? |v| = 32.8 m/s 1 Sy = SAV + ‚ + (v₁)t − 1 / 8 gt S₂ = Sµ |v₁ = V, mat A ±(v₁ )t v¸ = V₁ – gt y A ► 17 m/s A (0,0) Sx
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
p3.1
![• A stone is thrown horizontally at +17 m/s
from the top of a cliff 40 m high.
I.
How long does the stone take to
reach the bottom of the cliff?
t = 2.86 s
II.
How far from the base of the cliff
does the stone strike the ground?
Sx = 48.62 m
III.
What is the speed of the stone just
before it strikes the ground?
|v| = 32.8 m/s
|5y = 5 4y + (v₁) t = -1/2 & 1²
S
Ay
V₁ = V₁
A
|S₂ = $₁+ (v₂)t\v₂ = V₁ - gt
itten
A
A
► 17 m/s
A (0,0)
Sx](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F22332f98-1fb5-4298-bf69-b2fa3efeadf7%2Fec6b2dc3-30c1-40d3-a362-30ff9ea3cbf0%2Fqhq40to_processed.png&w=3840&q=75)
Transcribed Image Text:• A stone is thrown horizontally at +17 m/s
from the top of a cliff 40 m high.
I.
How long does the stone take to
reach the bottom of the cliff?
t = 2.86 s
II.
How far from the base of the cliff
does the stone strike the ground?
Sx = 48.62 m
III.
What is the speed of the stone just
before it strikes the ground?
|v| = 32.8 m/s
|5y = 5 4y + (v₁) t = -1/2 & 1²
S
Ay
V₁ = V₁
A
|S₂ = $₁+ (v₂)t\v₂ = V₁ - gt
itten
A
A
► 17 m/s
A (0,0)
Sx
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