How do you get the centroid of the inclined shape like in the picture? Like for F1 = PcgA1, you obviously need the centroid and the area, so how do you get it if it's inclined? Can anyone give an example?
How do you get the centroid of the inclined shape like in the picture? Like for F1 = PcgA1, you obviously need the centroid and the area, so how do you get it if it's inclined? Can anyone give an example?
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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CONCEPTUAL QUESTION - Hydrostatic Forces in Layered Fluids
How do you get the centroid of the inclined shape like in the picture? Like for F1 = PcgA1, you obviously need the centroid and the area, so how do you get it if it's inclined? Can anyone give an example?

Transcribed Image Text:2.7 Hydrostatic Forces in
Layered Fluids
The formulas for plane and curved surfaces in Secs. 2.5 and 2.6 are valid only for a
fluid of uniform density. If the fluid is layered with different densities, as in Fig. 2.15,
a single formula cannot solve the problem because the slope of the linear pressure
Plane
z= 0
surface
Pa
Fluid 1
p = P-P187
F2= P cG42
P = Pa- P187,
P2
Fluid 2
Z2. P2
p = P1 - P28(zz ?
Fig. 2.15 Hydrostatic forces on a
surface immersed in a layered fluid
must be summed in separate pieces.
P2 = P1 -P28(z, z 1
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