A Steel wire hangs vertically under its weight. What is the greatest length it can have if the allowable tensile stress o, =200 kN/m3.(ans:-2500 m) Solution: MPa? Density of steel y=80 O; =200 MPa= 200*103 kN/m² ; L y=80 kN/m³. Wt. of wire P=(Tt/4)(D²)(L)* y c/s area of wire A=(t/4)*D² Of = PIA solving above eq. L=2500m
A Steel wire hangs vertically under its weight. What is the greatest length it can have if the allowable tensile stress o, =200 kN/m3.(ans:-2500 m) Solution: MPa? Density of steel y=80 O; =200 MPa= 200*103 kN/m² ; L y=80 kN/m³. Wt. of wire P=(Tt/4)(D²)(L)* y c/s area of wire A=(t/4)*D² Of = PIA solving above eq. L=2500m
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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