A statistical program is recommended. Consider the following data for two variables, x and y. xi 4 5 7 8 10 12 12 22 yi 13 14 16 16 17 20 23 19 (a) Compute the standardized residuals for these data. (Round your answers to two decimal places.) xi yi Standardized Residuals 4 13 5 14 7 16 8 16 10 17 12 20 12 23 22 19 Do the data include any outliers? Explain. There are no standardized residuals that are less than −2 or greater than +2, so there are no possible outliers.There is one standardized residuals that is less than −2 or greater than +2, so there is one possible outlier. There are two standardized residuals that are less than −2 or greater than +2, so there are two possible outliers.There are more than two standardized residuals that are less than −2 or greater than +2, so there are more than two possible outliers. (b) Compute the leverage values for these data. (Round your answers to two decimal places.) xi yi Leverage Values 4 13 5 14 7 16 8 16 10 17 12 20 12 23 22 19 Do there appear to be any influential observations in these data? Explain. Minitab identifies an observation as having high leverage if hi > 6 n; for these data, 6 n = . Since the leverage for the observation at (xi, yi) =
A statistical program is recommended. Consider the following data for two variables, x and y. xi 4 5 7 8 10 12 12 22 yi 13 14 16 16 17 20 23 19 (a) Compute the standardized residuals for these data. (Round your answers to two decimal places.) xi yi Standardized Residuals 4 13 5 14 7 16 8 16 10 17 12 20 12 23 22 19 Do the data include any outliers? Explain. There are no standardized residuals that are less than −2 or greater than +2, so there are no possible outliers.There is one standardized residuals that is less than −2 or greater than +2, so there is one possible outlier. There are two standardized residuals that are less than −2 or greater than +2, so there are two possible outliers.There are more than two standardized residuals that are less than −2 or greater than +2, so there are more than two possible outliers. (b) Compute the leverage values for these data. (Round your answers to two decimal places.) xi yi Leverage Values 4 13 5 14 7 16 8 16 10 17 12 20 12 23 22 19 Do there appear to be any influential observations in these data? Explain. Minitab identifies an observation as having high leverage if hi > 6 n; for these data, 6 n = . Since the leverage for the observation at (xi, yi) =
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
A statistical program is recommended.
Consider the following data for two variables, x and y.
xi
|
4 | 5 | 7 | 8 | 10 | 12 | 12 | 22 |
---|---|---|---|---|---|---|---|---|
yi
|
13 | 14 | 16 | 16 | 17 | 20 | 23 | 19 |
(a)
Compute the standardized residuals for these data. (Round your answers to two decimal places.)
xi
|
yi
|
Standardized Residuals |
---|---|---|
4 | 13 | |
5 | 14 | |
7 | 16 | |
8 | 16 | |
10 | 17 | |
12 | 20 | |
12 | 23 | |
22 | 19 |
Do the data include any outliers? Explain.
There are no standardized residuals that are less than −2 or greater than +2, so there are no possible outliers.There is one standardized residuals that is less than −2 or greater than +2, so there is one possible outlier. There are two standardized residuals that are less than −2 or greater than +2, so there are two possible outliers.There are more than two standardized residuals that are less than −2 or greater than +2, so there are more than two possible outliers.
(b)
Compute the leverage values for these data. (Round your answers to two decimal places.)
xi
|
yi
|
Leverage Values |
---|---|---|
4 | 13 | |
5 | 14 | |
7 | 16 | |
8 | 16 | |
10 | 17 | |
12 | 20 | |
12 | 23 | |
22 | 19 |
Do there appear to be any influential observations in these data? Explain.
Minitab identifies an observation as having high leverage if
;
for these data,
= .
Since the leverage for the observation at
,
we conclude that this observation is an influential observation.
hi >
6 |
n |
6 |
n |
(xi, yi) =
is greater than
6 |
n |
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