A statistical program is recommended.An article reported data on potential drop measurements for one sample of connectors wired with alloy aluminum and another sample wired with EC aluminum. Does the accompanying computer output suggest that the true average potential drop for alloy connections (type 1) is higher than that for EC connections (as stated in the article)?Carry out the appropriate test using a significance level of 0.01. [Note: The computer output reports the P-value for a two-tailed test.] (Use μ, for alloy connections and for EC connections.)MeanType N2121P-value=12Std Dev16.49900000 0.6501282116.90000000 0.48998389VariancesTUnequal 3.7198 39.5Equal 3.7198DF Prob>ITI0.00060.000€Std Error0.120047820.10692326State the relevant hypotheses.OHH₁-H₂-OH:H₁-H₂>0O Hoi H₂-H₂ <0H₂H₁-H₂=0ⒸH₂H₂-H₂0H₂H₁ H₂ = 0OH₂H₁-H₂-OH₂H₂-1₂ 0OHH₂-H₂0H₂H₁ H₂ <0Find the test statistic and P-value using the output. (Enter your answers to four decimal places.)State the conclusion in the problem context.O Fail to reject H.. The data suggest that the true average potential drop for alloy connections is higher than that for EC connections.O Reject H. The data do not suggest that the true average potential drop for alloy connections is higher than that for EC connections.O Fail to reject H. The data do not suggest that the true average potential drop for alloy connections is higher than that for EC connections.O Reject H. The data suggest that the the true average potential drop for alloy connections is higher than that for EC connections.In reaching your conclusion, what type of error might you have committed?O Type I ErrorO Type II Error

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A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x = 101.16, y = 102.3, r= 0.810, P-value = 0.000, and y = 23.09+0.78x, where x represents the IQ score of the wife. Find the best %3D %3D %3D predicted value of y given that the wife has an IQ of 109? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. .... The best predicted value of y is . (Round to two decimal places as needed.) Critical values of the pearson correlation coefficient r NOTE: To test Ho: p = 0 against H,: p#0, reject Ho |if the absolute value of r is greater than the critical value in the table. a = 0.05 a = 0.01 4 0.950 0.990 0.878 0.959 0.811 0.917 0.754 0.875 0.707 0.834 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444 0.561 25 0.396 0.505 30 0.361 0.463 35 0.335 0.430 40…
An avionics company uses a new production method to manufacture aircraft altimeters. A single random sample of new altimeters resulted in the errors listed below. Use a 5% significance level to test the claim that the new production method has errors with a standard deviation greater than 32.2 ft, which was the standard deviation for the old production model (o). If it appears that the standard deviation is greater, does the new production method appear to be better or worse than the old method? Should the company take any action? -42 78 -22 -72 -45 15 17 51 -5 -53 -9 -109 Find the upper and lower boundaries of the 95% confidence interval for o. 98 37 32 73 89
3.18. A manufacturer of television sets is interested in the effect on tube conductivity of four different types of coating for color picture tubes. A completely randomized experiment is conducted and the following conductivity data are obtained: Coating Type 1 234 2 4 143 152 134 129 Conductivity 150 137 132 132 141 149 136 127 146 143 127 129 (a) Is there a difference in conductivity due to coating type? Use a = 0.05. (b) Estimate the overall mean and the treatment effects. (c) Compute a 95 percent confidence interval estimate of the mean of coating type 4. Compute a 99 percent confidence interval estimate of the mean difference between coating types 1 and 4.
You may need to use the appropriate technology to answer this question. Submitted The following table contains observed frequencies for a sample of 200. Column Variable Row Variable A B C P 20 44 50 Q 30 26 30 Test for independence of the row and column variables using a = 0.05. State the null and alternative hypotheses. Ho: The column variable is independent of the row variable. H: The column variable is not independent of the row variable. Ho: Variable P is not independent of variable Q. H: Variable P is independent of variable Q. Ho: Variable P is independent of variable Q. H: Variable P is not independent of variable Q. : The column variable is not independent of the row variable. Ho: : The column variable is independent of the row variable. Find the value of the test statistic. (Round your answer to three decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value %3D State your conclusion. Reject Ho. We conclude that the column and row variables are…
My answer is as follows: T critical = 2.70 T value= 7.775 P< a (0.01) Therefore we reject the null. Is this correct?
widely used as dielectrics and coolants in electrical systems in the past. They were found to be a major environmental contaminant in the 1960s. In a study, the mean PCB content at each of thirteen sites was reported for the years 1982 and 1996 (from “The ratio of DDE to PCB concentrations in Great Lakes herring gull eggs and its use in interpreting contaminants data”, Journal of Great Lakes Research 24 (1): 12-31, 1998). The data are below.Site:12345678910111213198261.4864.4745.5059.7058.8175.9671.5738.0630.5139.7029.7866.8963.93199613.9918.2611.2810.0221.0017.3628.207.3012.809.4112.6316.8322.74(a) Which test would be more appropriate in this case: a t-test for the difference between two population means, or a paired t-test? Why?(b) Do the data provide sufficient evidence to support the claim that the mean PCB level has decreased in the region? Be sure to check all assumptions, write the null and alternative hypotheses, calculate the appropriate test statistic, calculate the p-value,…
5. We don't want predictor variables that are too highly correlated with each other or they are redundant (say ≥±.70) or multicollinear (2±.90), which means the variables are measuring pretty much the same thing so why have them all in the equation. What was the finding for redundancy between SPI Scientist and SPI Practitioner? a. No issue with redundancy since the shared variance between the two variables was only 4% (r2 = .04). b. There was an issue with redundancy between the two variables shared 62% of the variance in the relationship.
10.20 In a random sample of recent high school graduates, two characteristics were recorded (the average score and the number of correct answers for the SAT test). This information was classified as shown in Table 10.8. Is there a dependence between the number of correct answers on the SAT test and the average rankings statistically discernible at a level α = 0.01?
An engineer has designed a valve that will regulate water pressure on an automobile engine. The valve was tested on 250 engines and the mean pressure was 6.8pounds/square inch (psi). Assume the population variance is 0.810.81. If the valve was designed to produce a mean pressure of 6.7 psi, is there sufficient evidence at the 0.1 level that the valve performs above the specifications? Step 1 of 6: State the null and alternative hypotheses. Step 2 of 6: Find the value of the test statistic. Round your answer to two decimal places. Step 3 of 6: Specify if the test is one-tailed or two-tailed. Step 4 of 6: Find the P-value of the test statistic. Round your answer to four decimal places. Step 5 of 6: Identify the level of significance for the hypothesis test. Step 6 of 6: Make the decision to reject or fail to reject the null hypothesis.
atients suffering from rheumatic diseases or osteoporosis often suffer critical losses in bone mineral density (BMD). Alendronate is one medication prescribed to build or prevent further loss of BMD. Holcomb and Rothenberg (A-3) looked at 96 women taking alendronate to determine if a difference existed in the mean percent change in BMD among five different primary diagnosis classifications. Group 1 patients were diagnosed with rheumatoid arthritis (RA). Group 2 patients were a mixed collection of patients with diseases including lupus, Wegener’s granulomatosis and polyarteritis, and other vasculitic diseases (LUPUS). Group 3 patients had polymyalgia rheumatica or temporal arthritis (PMRTA). Group 4 patients had osteoarthritis (OA) and group 5 patients had osteoporosis (O) with no other rheumatic diseases identified in the medical record. Changes in BMD are shown in the following table. Discuss the Alendronate medication data in terms of variability. To determine if a difference…
An automobile manufacturer has given its van a 50.6 miles/gallon (MPG) rating. An independent testing firm has been contracted to test the actual MPG for this van since it is believed that the van has an incorrect manufacturer's MPG rating. After testing 220 vans, they found a mean MPG of 50.5. Assume the population variance is known to be 1.69. A level of significance of 0.01 will be used. Find the P-value of the test statistic. you may write the P-value as a range using interval notation, or as a decimal value rounded to four decimal places.

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